How to determine whether the sum of two numbers is 30 or one of the numbers is 30 in PHP

藏色散人
Release: 2023-03-12 06:20:01
Original
2438 people have browsed it

Hello~ Today I will give you a very basic and simple judgment question to test how deep your understanding of PHP operators is~

This question is like this: "Please write a PHP program to check two given integers and return true if one of them is 30 or their sum is 30".

Okay, let’s start doing the questions~ (Maybe it will be done in one minute, hahaha)

But newcomers can still consolidate the PHP operators through this type of questions Be knowledgeable and get started.

The following is the implementation method I gave:

The PHP code is as follows:

<?php
function test($x, $y)
{
    return ($x == 30) || ($y == 30) || ($x + $y == 30);
}

var_dump(test(30, 0));
var_dump( test(25, 5));
var_dump( test(20, 30));
var_dump(test(20, 25));
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The return result is as follows:

How to determine whether the sum of two numbers is 30 or one of the numbers is 30 in PHP

Then let me give you a brief introduction to the meaning of the above code:

First we define a test() through the function() keyword function, and two parameters $x, $y are given; then the judgment statement is implemented through the operators ==, ||, in the method body.

That is to say, if $x is equal to 30 or $y is equal to 30 or $x $y is equal to 30, the result will return true, otherwise it will return false; finally call the test function.

We can see that I have given four pairs of parameters, namely (30, 0), (25, 5), (20, 30), (20, 25); it can be clearly seen that the last one Will return false, others are true.

Attachment:

== belongs to the comparison operator, which means equal, for example, x == y, if x is equal to y, then returns true;

|| is a logical operator, indicating or, for example, x || y, if at least one of x and y is true, then true is returned;

Belongs to arithmetic operators and represents addition. For example, x y represents the sum of x and y.

Finally, I would like to recommend the latest and most comprehensive "PHP Video Tutorial"~ Come and learn!

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