How to determine whether a value is of type int in php
php method to determine whether a value is of type int: 1. Use the is_int() function, which is used to detect whether the variable is an integer, the syntax is "is_int($var)"; 2. Use the is_numeric() function , syntax "is_numeric($var)".
The operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer
php judgment value is Not an int type (integer)
Method 1: Use the is_int() function
is_int() function is used to detect whether the variable is an integer . Returns TRUE if the specified value is an integer, FALSE otherwise.
<?php header("Content-type:text/html;charset=utf-8"); $var_name1=678; $var_name2="a678"; $var_name3="678"; $var_name4=999; $var_name5=698.99; $var_name6=array("a1","a2"); $var_name7=+125689.66; if (is_int($var_name1)) { echo "$var_name1 是整数" . "<br>"; } else { echo "$var_name1 不是整数" . "<br>" ; } if (is_int($var_name2)) { echo "$var_name2 是整数" . "<br>" ; } else { echo "$var_name2 不是整数" . "<br>" ; } $result=is_int($var_name3); echo "[ $var_name3 是整数吗? ]" .var_dump($result) . "<br>"; $result=is_int($var_name4); echo "[ $var_name4 是整数吗? ]" .var_dump($result) . "<br>"; $result=is_int($var_name5); echo "[ $var_name5 是整数吗? ]" .var_dump($result) . "<br>"; $result=is_int($var_name6); echo "[ $var_name6 是整数吗? ]" .var_dump($result) . "<br>"; $result=is_int($var_name7); echo "[ $var_name7 是整数吗? ]" .var_dump($result); ?>
Method 2: Use is_numeric() function
is_numeric() function is used to detect whether the variable is a number or numeric character string.
<?php header("Content-type:text/html;charset=utf-8"); $var_name1=678; $var_name2=698.99; $var_name3=+125689.66; if (is_int($var_name1)) { echo "$var_name1 是整数" . "<br>" ; } else { echo "$var_name1 不是整数" . "<br>" ; } if (is_int($var_name2)) { echo "$var_name2 是整数" . "<br>" ; } else { echo "$var_name2 不是整数" . "<br>"; } if (is_int($var_name3)) { echo "$var_name3 是整数" . "<br>"; } else { echo "$var_name3 不是整数" . "<br>" ; } ?>
Note: The difference between the two functions is that when the variable is a numeric string such as '1'
,
The return value of is_int() is false,
The return value of is_numeric() is true
Recommended study: "PHP video tutorial》
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