How to determine whether the elements in an array are the same in php

Judgment method: 1. Remove duplicate values ​​in the array, syntax "$newArr=array_unique($arr);"; 2. Get the length of the array after deduplication. If the array length is 1, then the original array The elements in are all the same, the syntax is "if(count($newArr)==1){//Operation when they are all the same}".

The operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer

In php, you can use array_unique () and count() functions to determine whether the elements in the array are the same.

Implementation idea:

• Use array_unique() to remove duplicate values ​​in the array. If two or more array values ​​are the same, only the first value is retained and the other values ​​are removed.

• Use count() to obtain the length of the array after deduplication

  • If the array length is 1, it means that there is only one element in the original array , that is, the elements in the original array are all the same

  • If the array length is not 1, it means that not all the elements in the original array are the same

Implementation method:

1. Use array_unique() to remove duplicate values ​​in the array

<?php
$arr1 = array(1,1,1,1,1,1,1);
var_dump(array_unique($arr1));

$arr2 = array(1,2,1,3,1,1,1);
var_dump(array_unique($arr2));
?>

##2. Use count () Determine the length of the array after deduplication and determine whether the array length is 1

<?php
header(&#39;content-type:text/html;charset=utf-8&#39;);   
$arr = array(1,1,1,1,1,1,1);
$newArr=array_unique($arr);
if(count($newArr)==1){
	echo "数组中元素都相同";
}else{
	echo "数组中元素不是都相同";
}
?>

Extension: Improve the code and encapsulate it as a functional function:

<?php
header(&#39;content-type:text/html;charset=utf-8&#39;);   
function f($arr){
	$newArr=array_unique($arr);
	if(count($newArr)==1){
		echo "数组中元素都相同<br>";
	}else{
		echo "数组中元素不是都相同<br>";
	}
}
$arr1 = array(1,1,1,1,1,1,1);
$arr2 = array(1,2,1,3,1,1,1);
f($arr1);
f($arr2)
?>

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