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Is there a case statement in oracle?
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Is there a case statement in oracle?

May 31, 2022 am 10:34 AM
oracle

There is a case statement in Oracle; this statement can compare the expression result with several foreseeable results provided. If the comparison is successful, the corresponding statement sequence is executed. The syntax is "CASE expression WHEN expression Expression result 1 THEN executable item [WHEN expression result 2 THEN executable item]...".

Is there a case statement in oracle?

The operating environment of this tutorial: Windows 10 system, Oracle version 12c, Dell G3 computer.

Is there a case statement in oracle?

Is there a case statement in oracle?

case statements can be divided into two types:

One is a simple case statement, which gives an expression and compares the expression result with several foreseeable results provided. If the comparison is successful, the corresponding statement sequence is executed.

The other is the search-style case statement. It will provide multiple Boolean expressions, then select the first expression that is true and execute the corresponding script.

1. Simple case statement

 The syntax of simple case is as follows:

Is there a case statement in oracle?

 Enter 1 and 2 respectively to call The final result is as follows:

匿名块已完成
男人
匿名块已完成
女人
Copy after login

 From the above point of view, the simple syntax of case is as follows:

case 标志
when 参数1 then
语句块1;
when 参数2 then
语句块2;
else
语句块3;
end case;
Copy after login

 During the execution process, from top to bottom, take the parameters after when in order, and compare them with the above The flags are compared and entered if equal.

In addition, if the else above is not written, if there is no when that meets the conditions, a CASE_NOT_FOUND exception will be thrown.

2. Search-type case statement

 Search-type case is similar to the simple form, except that it is a search-type case, and there are no parameters after the case.

Modify the above example as follows, which is the search case:

Is there a case statement in oracle?

The execution process is the same as above.

 From the top, the search case syntax is as follows:

case 
when 条件1 then
语句块1;
when 条件2 then
语句块2;
else
语句块3;
end case;
Copy after login

 In the execution process, from top to bottom, check whether the conditions after when are true, and enter if true.

In addition, if the else above is not written, if there is no when that meets the conditions, a CASE_NOT_FOUND exception will also be thrown.

Recommended tutorial: "Oracle Video Tutorial"

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