How to find the number in an array that is divisible by 3 in php

Method: 1. Use the foreach statement to loop through the array, with the syntax "foreach($arr as $v){//loop body}"; 2. In the loop body, determine whether the array element "$v" It can be divisible by 3. If so, it will be output. The syntax is "if($v%3==0){echo $v."
";}".

The operating environment of this tutorial: windows7 system, PHP7.1 version, DELL G3 computer

php seeks the array Methods that can be divisible by 3

1. Use the foreach statement to loop through the array

foreach ($array as $value){
    //循环体语句块;
}

Traverse the given $array array, in each In the second loop, the value of the current array is assigned to $value.

2. In the loop body, determine whether the array element $value is divisible by 3. If so, output

if($value%3==0){
	echo $value."<br>";
}

Analysis:

• can be divisible by 3, in other words, the remainder after dividing by 3 is 0;

• Therefore, you can use the % operator to find the remainder, Just use == to determine whether the remainder is equal to 0.

Complete code:

<?php
header("Content-type:text/html;charset=utf-8");
$arr=array(2,3,5,6,7,8,9,17,20,12,15,25,24,81);
var_dump($arr);
foreach($arr as $value){
	if($value%3==0){
		echo $value."<br>";
	}
}
?>

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