This article will share with you 20 weird JavaScript expressions. Can you answer their output results? Come and answer the challenge!
#JavaScript is a very fault-tolerant programming language, and many expressions that are illegal in other programming languages will work fine in JavaScript.
This leads to a lot of weird code. Do you want to challenge it?
In this challenge, you will see 20 weird expressions and have to guess their output.
1.
true + false
2.
**1.**
3.
[1, 2, 3] + [4, 5, 6]
4.
0.2 + 0.1 === 0.3
5.
10,2
6.
!!""
7 .
+!![]
8.
true == "true"
9.
010 - 03
10.
"" - - ""
11.
null + 0
12.
0/0
13.
1/0 === 10 ** 1000
14.
true++
15.
"" - 1
16.
(null - 1) - "1"
17 .
38 * 4343 * 2342+ (“true” — 0)
18.
5 + !5 + !!5
19.
[] + [1] + 2
20.
1 + 2 + "3"
true false
When trying to use the addition operator ( ) between two Boolean values , they will be converted to numbers.
And we all know that true
should be converted to 1
and false
should be converted to 0
. So true false
returns 1
.
[,,,].length
[,,,]
Outputs an array with three empty slots. The last comma is the trailing comma.
You can think of it this way.
[,] ==> [empty,] [,,] ==> [empty, empty,] [,,,] ==> [empty, empty, empty,]
So [,,,].length
returns 3.
[1, 2, 3] [4, 5, 6]
When you try to use the addition operator ( ) between arrays, they are Convert to string.
When converting an array to a string, the array's toString()
method is called. toString()
The method is used internally by JavaScript. When an array needs to be displayed as text, it will connect its elements with commas.
[1, 2, 3].toString() ==> '1, 2, 3' [4, 5, 6].toString() ==> '4, 5, 6'
So
[1, 2, 3] + [4, 5, 6] ==> '1, 2, 3' + '4, 5, 6' ==> "1,2,34,5,6"
0.2 0.1 === 0.3
Since floating point numbers are difficult to accurately represent in computers, mathematical 0.1
and 0.2
can only be represented by approximate numbers in computers. The result of
0.1 0.2
is not exactly 0.3
. Not just JavaScript, other programming languages have the same problem.
10, 2
The comma (,
) is also a legal operator in JavaScript, it evaluates each operand (from left to right to the right) and returns the value of the last operand.
Therefore, 10,2 returns 2
!!""
""
is an empty string, it is a false value.
Note: 0, empty string "", null and undefined are all virtual values.
!
is the logical "not" operator, turning true into false and vice versa.
If we use !
twice, which is !!
, it will convert a normal value into a boolean value. So !""
returns false
.
!![]
Arrays are all true values, even empty arrays. So !![]
will return true
.
!![]; // -> true
and
will convert the true value to its numeric representation: 1
, so !![]
returns 1
.
true == "true"
The double equality operator (==) checks whether its two operands are equal and returns a Boolean result.
According to the abstract equality comparison rules, both values are converted to numbers when compared.
true == "true" ==> Number(true) == Number("true") ==> 1 == NaN
So, ture == "true"
Return false.
010 - 03
Here’s a little trick: if a number starts with 0
, it is treated as Make an octal number. So:
010 - 03 ==> 8 - 3 ==> 5
Also:
""--""
This looks like a bad syntax , but it does work fine.
The empty string can be converted to the Boolean value false or the numeric value 0. So -""
is 0
##null 0
正如我们之前所说,null
是一个虚值。它将被转换为布尔值false
或数字值0
。所以结果返回 0
。
0/0
这是一个非法的数学表达式。方程0/0没有任何有意义的数字答案,输出的结果只是NaN
。
1/0 === 10 1000**
虽然1/0
和之前一样也是一个非法的数学表达式。但是当除数不是0
时,JavaScript认为这个表达式的结果是Infinity
。
而10**1000
是一个很大数字,JS 无法正确表示这个数字。(JavaScript中最高的整数值是2^53-1
)。所以10 * 1000
也被当作无限大(Infinity)。
无穷大总是等于另一个无穷大,所以1/0 === 10 ** 1000
返回 true。
true++
这没有什么特别的,这只是一个语法错误。
""- 1
虽然加法运算符(+)同时用于数字和字符串,但减法运算符(-)对字符串没有用处,所以JavaScript将其解释为数字之间的操作。一个空的字符串会被类型强制为0。
"" - 1 ==> Number("") - 1 ==> 0 - 1 ==> -1
所以 "" — 1
返回 -1
(null - 1) - "1"
正如上面所说。
null ==> 0 (null - 1) ==> -1 "1" ==> 1
所以 (null — 1) — “1”
返回 -2
38 4343 2342+ ("true" - 0)
你可能会怀疑JS是如此疯狂,以至于它将字符串 "true" 转换为布尔值 true 的数字表示。然而,它并没有那么疯狂。实际发生的情况是,它试图将字符串转换为数字,但失败了。
Number("true"); // -> NaN
在JavaScript的数字运算中,只要有一个值是NaN,运算的最终结果就一定是NaN。38 * 4343 * 2342
只是一个烟雾弹。
5 + !5 + !!5
正如上面所说。
所以:
!5 ==> 0 !!5 ==> 1
[] + [1] + 2
试图在数组之间使用加法运算符(+)时,它们会被转换为字符串。
[] ==> '' [1] ==> '1' [] + [1] ==> '1' '1' + 2 ==> '12'
所以结果是'12'。
1 + 2 + "3"
JavaScript 从左到右执行这些操作。当数字3与字符串3相加时,字符串连接将优先进行。
1 + 2; // -> 3 3 + "3"; // -> "33"
坦率地说,这些挑战并没有为我胶们编码技能提供任何价值,所以不应该在实际项目中写这种代码
但是,把这些技巧作为朋友和同事之间的一些装13,不是一件非常有趣的事情吗?
作者:Marina Mosti
来源:medium
原文:https://medium.com/frontend-canteen/20-useless-but-funny-challange-for-javascript-develor-9eea39bb8efb
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