With the continuous development of front-end technology, the interfaces that need to be displayed in front-end work are becoming more and more complex, so there are more and more data processing scenarios. For example: back-end management systems often need to display A tree structure, the front-end data returned by the background is a horizontal structure. At this time, we need to convert the data into a tree structure; when displaying the echart histogram, the returned data needs to be deduplicated and merged; when filtering, we The data needs to be sorted; the most common ones are the addition, deletion, modification and checking of Dom when we leave messages and comments, etc. So today's article will take you into these business scenarios and face these difficult problems head-on. Let's face them No longer be afraid of JavaScript data operations, making development work simpler and more efficient.
Scenario: This is a background management system - the dictionary management module, which includes four operations of adding, deleting, modifying and checking the data dictionary. So what is our solution to deal with these 4 operations? Please read on below
arr.push Push one or more elements from the back of the array
var arr = [1,2,3]; // 返回：修改后数组的长度 arr.push(4,5,6); console.log(arr) //输出结果 arr=[1,2,3,4,5,6]
arr.unshift Add one or more elements from the front of the array
var arr = [1,2,3]; // 返回：修改后数组的长度 arr.unshift(4,5,6); console.log(arr) //输出结果 arr=[4,5,6,1,2,3]
arr.shift is used to remove the first element of the array
// 数组的shift方法用于将数组的第一个元素移除 var arr = [1,2,3]; // 返回 被删除的元素； arr.shift(); //输出结果 arr=[2,3]
arr.pop Delete the last element of the array;
// 数组的pop方法用于将数组的最后一个元素移除 var arr = [1,2,3]; // 返回 被删除的元素； arr.pop(); //输出结果 arr = [1,2];
arr.splice: Yes Add, delete, and modify any position of the array Then an empty array is returned))
Syntaxsplice(index,howmany,item1,…itemx);
index—— Must be an integer that specifies the position to add or delete. Use a negative number to specify the position from the end of the array.
1. 删除 可删除任意数量的项，只需指定2个参数：要删除的第一项的位置和要删除的项数。 let arr=[1,2,3]; let arr1=arr.splice(1,2);//会删除数组的第2和3个元素（即2,3） alert(arr);//[1] alert(arr1);//[2,3] 2. 插入 可以向指定位置插入任意数量的项只需提供3个参数：起始位置、0（要删除的项数）、要插入的项。 let arr=[1,2,3]; let arr1=arr.splice(1,0,4,5);//会从数组的1位置开始插入4,5 alert(arr);//[1,4,5,2,3] alert(arr1);//[] 3. 替换 可以向指定位置插入任意数量的项，且同时删除任意数量的项，只需指定3个参数：起始位置、要删除的项数和要插入的任意数量的项（插入的数量不必与删除的数量相等） let arr = [1,2,3]; let arr1=arr.splice(1,1,"red","green");//会删除2，然后从2位置插入字符串"red"和"green" alert(arr);//[1,"red","green",3] alert(arr1);//[2]
var arr = [10,20,30] console.log(arr.indexOf(30)); // 2 console.log(arr.indexOf(40)); // -1
var arr = [10, 20, 30];
var res1 = arr.findIndex(function (item) {
return item >= 20;
});
// 返回 满足条件的第一个元素的的索引
console.log(res1);var arr = ['用户1','用户2','用户3'];
var str = arr.join('|');
console.log(str); //
用户1|用户2|用户3// 这个方法用于将一个字符串以指定的符号分割成数组
var str = '用户1|用户2|用户3';
var arr = str.split('|');
console.log(arr);
['用户1','用户2','用户3']
1. js’s own function arr.sort()
var arr = [23,34,3,4,23,44,333,444];
arr.sort(function(a,b){
return a-b;
})
console.log(arr);var arr = [23,34,3,4,23,44,333,444];
var arrShow = (function insertionSort(array){
if(Object.prototype.toString.call(array).slice(8,-1) ==='Array'){
for (var i = 1; i < array.length; i++) {
var key = array[i];
var j = i - 1;
while (j >= 0 && array[j] > key) {
array[j + 1] = array[j];
j--;
}
array[j + 1] = key;
}
return array;
}else{
return 'array is not an Array!';
}
})(arr);
console.log(arrShow);//[3, 4, 23, 23, 34, 44, 333, 444]function binaryInsertionSort(array) {
if (Object.prototype.toString.call(array).slice(8, -1) === 'Array') {
for (var i = 1; i < array.length; i++) {
var key = array[i], left = 0, right = i - 1;
while (left <= right) {
var middle = parseInt((left + right) / 2);
if (key < array[middle]) {
right = middle - 1;
} else {
left = middle + 1;
}
}
for (var j = i - 1; j >= left; j--) {
array[j + 1] = array[j];
}
array[left] = key;
}
return array;
} else {
return 'array is not an Array!';
}
}function selectionSort(array) {
if (Object.prototype.toString.call(array).slice(8, -1) === 'Array') {
var len = array.length, temp;
for (var i = 0; i < len - 1; i++) {
var min = array[i];
for (var j = i + 1; j < len; j++) {
if (array[j] < min) {
temp = min;
min = array[j];
array[j] = temp;
}
}
array[i] = min;
}
return array;
} else {
return 'array is not an Array!';
}
}function bubbleSort(array) {
if (Object.prototype.toString.call(array).slice(8, -1) === 'Array') {
var len = array.length, temp;
for (var i = 0; i < len - 1; i++) {
for (var j = len - 1; j >= i; j--) {
if (array[j] < array[j - 1]) {
temp = array[j];
array[j] = array[j - 1];
array[j - 1] = temp;
}
}
}
return array;
} else {
return 'array is not an Array!';
}
}//方法一
function quickSort(array, left, right) {
if (Object.prototype.toString.call(array).slice(8, -1) === 'Array' && typeof left === 'number' && typeof right === 'number') {
if (left < right) {
var x = array[right], i = left - 1, temp;
for (var j = left; j <= right; j++) {
if (array[j] <= x) {
i++;
temp = array[i];
array[i] = array[j];
array[j] = temp;
}
}
quickSort(array, left, i - 1);
quickSort(array, i + 1, right);
};
} else {
return 'array is not an Array or left or right is not a number!';
}
}
var aaa = [3, 5, 2, 9, 1];
quickSort(aaa, 0, aaa.length - 1);
console.log(aaa);
//方法二
var quickSort = function(arr) {
if (arr.length <= 1) { return arr; }
var pivotIndex = Math.floor(arr.length / 2);
var pivot = arr.splice(pivotIndex, 1)[0];
var left = [];
var right = [];
for (var i = 0; i < arr.length; i++){
if (arr[i] < pivot) {
left.push(arr[i]);
} else {
right.push(arr[i]);
}
}
return quickSort(left).concat([pivot], quickSort(right));
};/*方法说明：堆排序
@param array 待排序数组*/
function heapSort(array) {
if (Object.prototype.toString.call(array).slice(8, -1) === 'Array') {
//建堆
var heapSize = array.length, temp;
for (var i = Math.floor(heapSize / 2); i >= 0; i--) {
heapify(array, i, heapSize);
}
//堆排序
for (var j = heapSize - 1; j >= 1; j--) {
temp = array[0];
array[0] = array[j];
array[j] = temp;
heapify(array, 0, --heapSize);
}
} else {
return 'array is not an Array!';
}
}
/*方法说明：维护堆的性质
@param arr 数组
@param x 数组下标
@param len 堆大小*/
function heapify(arr, x, len) {
if (Object.prototype.toString.call(arr).slice(8, -1) === 'Array' && typeof x === 'number') {
var l = 2 * x, r = 2 * x + 1, largest = x, temp;
if (l < len && arr[l] > arr[largest]) {
largest = l;
}
if (r < len && arr[r] > arr[largest]) {
largest = r;
}
if (largest != x) {
temp = arr[x];
arr[x] = arr[largest];
arr[largest] = temp;
heapify(arr, largest, len);
}
} else {
return 'arr is not an Array or x is not a number!';
}
}好的，当我们解决完排序的问题，紧接着我们又面临着数据去重的问题，不要怕，解决方案依然有很多，请您慢慢往下接着看：
在工作上,对json数据处理时,例如遇到对某些产品的尺码进行排序,不同的产品都有相同的尺码那是正常不过的事情,如果我们要把这些转成表格的形式来展现,那么这些尺码就不要不能重复才行.在这里呢,我就写几个数组去重的方法,给大家参考参考 ：
// 最简单数组去重法
/*
* 新建一新数组，遍历传入数组，值不在新数组就push进该新数组中
* IE8以下不支持数组的indexOf方法
* */
function uniq(array){
var temp = []; //一个新的临时数组
for(var i = 0; i < array.length; i++){
if(temp.indexOf(array[i]) == -1){
temp.push(array[i]);
}
}
return temp;
}
var aa = [1,2,2,4,9,6,7,5,2,3,5,6,5];
console.log(uniq(aa));/*
* 速度最快， 占空间最多（空间换时间）
*
* 该方法执行的速度比其他任何方法都快， 就是占用的内存大一些。
* 现思路：新建一js对象以及新数组，遍历传入数组时，判断值是否为js对象的键，
* 不是的话给对象新增该键并放入新数组。
* 注意点：判断是否为js对象键时，会自动对传入的键执行“toString()”，
* 不同的键可能会被误认为一样，例如n[val]-- n[1]、n["1"]；
* 解决上述问题还是得调用“indexOf”。*/
function uniq(array){
var temp = {}, r = [], len = array.length, val, type;
for (var i = 0; i < len; i++) {
val = array[i];
type = typeof val;
if (!temp[val]) {
temp[val] = [type];
r.push(val);
} else if (temp[val].indexOf(type) < 0) {
temp[val].push(type);
r.push(val);
}
}
return r;
}
var aa = [1,2,"2",4,9,"a","a",2,3,5,6,5];
console.log(uniq(aa));/*
* 给传入数组排序，排序后相同值相邻，
* 然后遍历时,新数组只加入不与前一值重复的值。
* 会打乱原来数组的顺序
* */
function uniq(array){
array.sort();
var temp=[array[0]];
for(var i = 1; i < array.length; i++){
if( array[i] !== temp[temp.length-1]){
temp.push(array[i]);
}
}
return temp;
}
var aa = [1,2,"2",4,9,"a","a",2,3,5,6,5];
console.log(uniq(aa));/*
*
* 还是得调用“indexOf”性能跟方法1差不多，
* 实现思路：如果当前数组的第i项在当前数组中第一次出现的位置不是i，
* 那么表示第i项是重复的，忽略掉。否则存入结果数组。
* */
function uniq(array){
var temp = [];
for(var i = 0; i < array.length; i++) {
//如果当前数组的第i项在当前数组中第一次出现的位置是i，才存入数组；否则代表是重复的
if(array.indexOf(array[i]) == i){
temp.push(array[i])
}
}
return temp;
}
var aa = [1,2,"2",4,9,"a","a",2,3,5,6,5];
console.log(uniq(aa));// 思路：获取没重复的最右一值放入新数组
/*
* 推荐的方法
*
* 方法的实现代码相当酷炫，
* 实现思路：获取没重复的最右一值放入新数组。
* （检测到有重复值时终止当前循环同时进入顶层循环的下一轮判断）*/
function uniq(array){
var temp = [];
var index = [];
var l = array.length;
for(var i = 0; i < l; i++) {
for(var j = i + 1; j < l; j++){
if (array[i] === array[j]){
i++;
j = i;
}
}
temp.push(array[i]);
index.push(i);
}
console.log(index);
return temp;
}
var aa = [1,2,2,3,5,3,6,5];
console.log(uniq(aa));呐，在选择部门的时候，是不是会经常看到这种树状菜单，后台返回的数据一般都是平级的数组，那么这种菜单，我们一般是怎么生成的呢，请看~~
const dataTree = [
{id: 1, name: '总公司', parentId: 0},
{id: 2, name: '深圳分公司', parentId: 1},
{id: 3, name: '北京分公司', parentId: 1},
{id: 4, name: '研发部门', parentId: 2},
{id: 5, name: '市场部门', parentId: 2},
{id: 6, name: '测试部门', parentId: 2},
{id: 7, name: '财务部门', parentId: 2},
{id: 8, name: '运维部门', parentId: 2},
{id: 9, name: '市场部门', parentId: 3},
{id: 10, name: '财务部门', parentId: 3},
]
function changeData(data, parentId = 0) {
let tree = [];//新建空数组
//遍历每条数据
data.map((item) => {
//每条数据中的和parentId和传入的相同
if (item.parentId == parentId) {
//就去找这个元素的子集去 找到元素中parentId==item.id 这样层层递归
item.children = changeData(data, item.id);
tree.push(item);
}
})
return tree
}
console.log(changeData(dataTree, 0));
我们在图表展示的时候会经常遇到数据处理，其中数组合并处理也会经常遇到，下面就是数组相同项合并的一种方式：
1、博主特意将珍藏多年的祖传代码，在这里奉献给各位大佬：
var arr = [
{"id":"1","name":"车厘子","num":"245"},
{"id":"1","name":"车厘子","num":"360"},
{"id":"2","name":"苹果","num":"120"},
{"id":"2","name":"苹果","num":"360"},
{"id":"2","name":"苹果","num":"180"},
{"id":"3","name":"香蕉","num":"160"},
{"id":"4","name":"菠萝","num":"180"},
{"id":"4","name":"菠萝","num":"240"}
];
var map = {},result= [];
for(var i = 0; i < arr.length; i++){
var ele = arr[i];
if(!map[ele.id]){
result.push({
id: ele.id,
name: ele.name,
value: ele.value
});
map[ele.id] = ele;
}else{
for(var j = 0; j < result.length; j++){
var dj = result[j];
if(dj.id == ele.id){
dj.value=(parseFloat(dj.value) + parseFloat(ele.value)).toString();
break;
}
}
}
};
console.log(result);看到这里 ，前端常见的几种数据处理的疑难杂症已经解决的差不多了，当然呐，现实情况下还有许许多多的问题未收录进来，后续会陆陆续续慢慢更新收录下来，同时呢也希望有遇到JavaScript数据处理比较头疼的朋友可以与博主交流探讨，有好的解题思路的也可以反馈给到博主。
以上就是今天要讲的全部内容，本文介绍了JavaScript开发过程中常见的5种数据处理问题并提供了对应的解决思路，基本覆盖了日常开发过程中的使用需求， 阅读本片文章可以大大提升你的javaScript基本功，在收到开发需求时，能快速响应，并给出解决方案。
【相关推荐：javascript视频教程、web前端】
The above is the detailed content of Organize and share 5 common data processing problems in JavaScript development. For more information, please follow other related articles on the PHP Chinese website!
![JavaScript core tutorial [DOM BOM operations that JS must know]](https://img.php.cn/upload/course/000/000/041/61c56ae28d02a390.jpg)
![JavaScript in-depth analysis [Web front-end must know basic skills]](https://img.php.cn/upload/course/000/000/041/61d3ff1c83b43350.jpg)
![TypeScript introductory video [can be understood even without learning JavaScript]](https://img.php.cn/upload/course/000/000/068/6242c0fc4be39373.png)
![Practical development of imitation Meituan APP [A must-have JavaScript project for front-end programmers]](https://img.php.cn/upload/course/000/000/068/6242bebc05ca9210.png)
![JavaScript basic syntax [dom|bom|es6 new syntax|jQuery|data visualization echarts]](https://img.php.cn/upload/course/000/000/068/6242bb730fb11708.png)
![[Web front-end] Node.js quick start](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
