How to determine whether an element is in a two-dimensional array in php

Judgment steps: 1. Use the foreach statement to loop through the outer array elements of the two-dimensional array, with the syntax ""foreach($arr as $v){//loop body code}""; 2. In In the loop body, use "if(is_array($v)){if(array_search(element value,$v)){//Specify the element in the two-dimensional array}}else{if($v===element value) {//The specified element is in the two-dimensional array}}" statement determines whether the specified element is in the two-dimensional array.

The operating environment of this tutorial: windows7 system, PHP8.1 version, DELL G3 computer

php determines whether the element is Methods in two-dimensional arrays

Step 1. Use the foreach statement to loop through the outer array elements of the two-dimensional array

foreach($arr as $v){
//循环体代码
}

Traverse Given the $arr array, the value of the current array will be assigned to $v in each loop.

Step 2. In the loop body, determine whether the element is in the two-dimensional array

Use the is_array() function to determine whether the outer element is of array type (whether it is Subarray)

• If yes, use array_search() to determine whether the specified element is in the subarray

• If not, use "=== "Just determine whether the current element is the specified element

if(is_array($v)){
	if(array_search(7,$v)){
		echo "指定元素在二维数组中";
		break;
	}
}else{
	if($v===7){
		echo "指定元素在二维数组中";
		break;
	}
}

Complete implementation code:

Improve it:

<?php
header("content-type:text/html;charset=utf-8");
function f($val,$arr) {
	$con = 0;
	foreach ($arr as $v) {
		if (is_array($v)) {
			if (array_search($val, $v)) {
				$con = 1;
				break;
			}
		} else {
			if ($v === $val) {
				$con = 1;
				break;
			}
		}
	}
	if ($con == 1) {
		echo "指定元素 $val 在二维数组中<br>";
	} else {
		echo "指定元素 $val 不在二维数组中<br>";
	}
}
$arr = array(1, 2, 3, array(4, 5, 6), 7, 8, array(9, 10));
var_dump($arr);
f("h",$arr);
f(7,$arr);
?>

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