What should I do if PHP fails to modify database data?
Solution for unsuccessful modification of database data in php: 1. Open the corresponding PHP file; 2. Obtain the user account and password and connect to the database; 3. Use the username variable to modify the data in the data table; 4. View Error message; 5. Check whether $db is connected correctly and modify it; 6. Check whether the table field name involved in sql in the prepare method is incorrect and modify it correctly.
The operating environment of this tutorial: Windows 7 system, PHP version 8.1, Dell G3 computer.
What should I do if php fails to modify the database data?
Problem description:
PHP cannot modify the database data
I have been stuck in ERROR for a whole day, please help me.
The core error report is as shown in the figure:
The complete code is here:
<?php header('Content-Type:textml;charset=utf-8'); $username='游客'; //获取用户输入的账号和密码并连接数据库 $account=$_POST['account']; $password=$_POST['password']; $db=new mysqli('localhost','root','12345678','newsmanage'); //查询数据库是否已经有相同账号 $query1=$db->prepare("SELECT account FROM user"); $query1->bind_result($theaccount); $query1->execute(); while($query1->fetch()) { if ($account == $theaccount) { echo '<script>alert("该账号已被注册!"); location.href="register.html"</script>'; exit(); } } //将用户输入的账号和密码写入数据库 $add=$db->prepare("INSERT INTO user VALUES (null,'general',null,?,?)"); $add->bind_param('ss',$account, $password); $add->execute(); //数据库对添加的新用户自动生成唯一ID,查寻此ID并赋值变量 $query2=$db->prepare("SELECT userid FROM user WHERE account='$account'"); $query2->bind_result($userid); $query2->execute(); $query2->fetch(); //用username变量修改数据表中的数据 $edit=$db->prepare("UPDATE user SET username=? WHERE account=?"); $edit->bind_param('ss',$username,$account); $edit->execute(); //报错提示:Call to a member function bind_param() on boolean in echo '<script>alert("恭喜您,注册成功!"); location.href="../login/login.html"</script>';
Problem analysis:
The error message has made it very clear, saying that you used a member function on a bool value. This error message indicates that your $db->prepare() method failed to execute and returned false instead of the mysqli_stmt object. Please confirm whether $db is connected correctly and whether the table field names involved in the sql in the prepare method are incorrect. and other questions that I can't think of at the moment. . .
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