Home > Backend Development > PHP Problem > How to output mysql error in php

How to output mysql error in php

藏色散人
Release: 2023-03-17 13:42:01
Original
1861 people have browsed it

php method to output mysql errors: 1. Create a new php file; 2. Create three variables, namely database address variable, database account variable and database password variable; 3. Use the mysqli_connect function to connect to the database; 4. . Use the if statement to determine whether the database connection is successful. If not, use the mysqli_error() function to output the error message.

How to output mysql error in php

The operating environment of this tutorial: Windows 7 system, PHP version 8.1, Dell G3 computer.

php How to output mysql error?

php mysql outputs the error message for connecting to the database

Create a new php file named test.php to explain how php mysql outputs the error message for connecting to the database.

How to output mysql error in php

In the test.php file, use the header() method to set the encoding format of the page to utf-8.

How to output mysql error in php

In the test.php file, create three variables, namely database address variable, database account variable, and database password variable.

How to output mysql error in php

In the test.php file, use the mysqli_connect function to connect to the database through the account number and password.

How to output mysql error in php

In the test.php file, use the if statement to determine whether the database connection is successful. If not, use the mysqli_error() function to output an error message. Otherwise, it will prompt "Database connection Success!"

How to output mysql error in php

#Open the test.php file in the browser to view the results.

How to output mysql error in php

Recommended study: "PHP Video Tutorial"

The above is the detailed content of How to output mysql error in php. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template