Modification method: 1. Use the append() function to add new values, the syntax "append(slice, value list)"; 2. Use the append() function to delete elements, the syntax "append(a[:i]" , a[i N:]...)"; 3. Reassign the value directly according to the index, the syntax is "slice name [index] = new value".
The operating environment of this tutorial: Windows 7 system, GO version 1.18, Dell G3 computer.
Add, delete, modify and query slices in Go language
package main import "fmt" func main() { a := []int{} a = append(a, 1) a = append(a, 2) a = append(a, 3, 4, 5) //添加多个元素 fmt.Printf("a: %v\n", a) fmt.Println("---------------------") a1 := []int{3, 4, 5} a2 := []int{1, 2} a2 = append(a2, a1...) //添加另外一个切片进去 fmt.Printf("a2: %v\n", a2) } //输出结果如下 a: [1 2 3 4 5] --------------------- a2: [1 2 3 4 5]
package main import "fmt" func main() { var s1 = []int{1, 2, 3, 4} fmt.Println("---删除之前---") fmt.Printf("s1: %v\n", s1) //删除3这个元素,它的下标索引为2 s1 = append(s1[:2], s1[3:]...) fmt.Println("---删除之后---") fmt.Printf("s1: %v\n", s1) } //执行结果如下 ---删除之前--- s1: [1 2 3 4] ---删除之后--- s1: [1 2 4]
Formula for deleting elements:
To delete the element with index index from slice a, the operation method is as follows
a = append(a[:index], a[index+1:]...)
package main import "fmt" func main() { var s1 = []int{1, 2, 3, 4, 5} s1[1] = 100 //索引1的值改为100 fmt.Printf("s1: %v\n", s1) } //输出结果如下 s1: [1 100 3 4 5]
package main import "fmt" func main() { var s1 = []int{1, 2, 3, 4, 5} var key = 2 //查找2所在的位置 for i, v := range s1 { if v == key { fmt.Printf("s1: %v\n", s1) fmt.Printf("索引为: %v\n", i) } } } //输出结果如下 s1: [1 2 3 4 5] 索引为: 1
package main import "fmt" func main() { var s1 = []int{1, 2, 3, 4, 5} var s2 = s1 s2[0] = 100 fmt.Printf("s1: %v\n", s1) fmt.Printf("s2: %v\n", s2) } //输出结果如下 s1: [100 2 3 4 5] s2: [100 2 3 4 5]
package main import "fmt" func main() { var s1 = []int{1, 2, 3, 4, 5} var s2 = make([]int, 4) //需要make一个切片的类型,指定有5个元素 copy(s2, s1) //指定复制的切片 s2[0] = 100 fmt.Printf("s1: %v\n", s1) fmt.Printf("s2: %v\n", s2) } //输出结果 s1: [1 2 3 4 5] s2: [100 2 3 4 5]
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