Home > Database > Mysql Tutorial > MYSQL锁表问题的解决方法_MySQL

MYSQL锁表问题的解决方法_MySQL

PHP中文网
Release: 2016-05-27 13:45:20
Original
1271 people have browsed it

本文实例讲述了MYSQL锁表问题的解决方法。分享给大家供大家参考,具体如下:

很多时候!一不小心就锁表!这里讲解决锁表终极方法!

案例一


mysql>show processlist;
Copy after login


参看sql语句

一般少的话


mysql>kill thread_id;
Copy after login


就可以解决了

kill掉第一个锁表的进程, 依然没有改善. 既然不改善, 咱们就想办法将所有锁表的进程kill掉吧, 简单的脚本如下.


#!/bin/bash
mysql - u root - e " show processlist " | grep - i " Locked " >> locked_log . txt
for line in ` cat locked_log.txt | awk '{print $1 }' `
do
echo " kill $line ; " >> kill_thread_id . sql
done
Copy after login


现在kill_thread_id.sql的内容像这个样子


kill 66402982 ;
kill 66402983 ;
kill 66402986 ;
kill 66402991 ;
.....
Copy after login


好了, 我们在mysql的shell中执行, 就可以把所有锁表的进程杀死了.


mysql > source kill_thread_id . sql
Copy after login


当然了, 也可以一行搞定


for id in `mysqladmin processlist | grep -i locked | awk '{print $1}'`
do
mysqladmin kill ${id}
done
Copy after login


案例二

如果大批量的操作能够通过一系列的select语句产生,那么理论上就能对这些结果批量处理。

但是mysql并没用提供eval这样的对结果集进行分析操作的功能。所以只能现将select结果保存到临时文件中,然后再执行临时文件中的指令。

具体过程如下:


mysql> SELECT concat('KILL ',id,';') FROM information_schema.processlist WHERE user='root';
+------------------------+
| concat('KILL ',id,';')
+------------------------+
| KILL 3101;      
| KILL 2946;      
+------------------------+
2 rows IN SET (0.00 sec)
mysql> SELECT concat('KILL ',id,';') FROM information_schema.processlist WHERE user='root' 
INTO OUTFILE '/tmp/a.txt';
Query OK, 2 rows affected (0.00 sec)
mysql> source /tmp/a.txt;
Query OK, 0 rows affected (0.00 sec)
Copy after login


案例三

MySQL + PHP的模式在大并发压力下经常会导致MySQL中存在大量僵死进程,导致服务挂死。为了自动干掉这些进程,弄了个脚本,放在服务器后台通过crontab自动执行。发现这样做了以后,的确很好的缓解了这个问题。把这个脚本发出来和大家Share.

根据自己的实际需要,做了一些修改:

SHELL脚本:mysqld_kill_sleep.sh


#!/bin/sh
mysql_pwd="root的密码"
mysqladmin_exec="/usr/local/bin/mysqladmin"
mysql_exec="/usr/local/bin/mysql"
mysql_timeout_dir="/tmp"
mysql_timeout_log="$mysql_timeout_dir/mysql_timeout.log"
mysql_kill_timeout_sh="$mysql_timeout_dir/mysql_kill_timeout.sh"
mysql_kill_timeout_log="$mysql_timeout_dir/mysql_kill_timeout.log"
$mysqladmin_exec -uroot -p"
$mysql_pwd" processlist | awk '{ print $12 , $2 ,$4}' | grep -v Time | grep -v '|' | sort -rn > 
$mysql_timeout_log
awk '{if($1>30 && $3!="root") print "'""$mysql_exec""' -e " "\"" "kill",$2 "\"" " -uroot " "-p""\"""'""$
mysql_pwd""'""\"" ";" }' $mysql_timeout_log > $mysql_kill_timeout_sh
echo "check start ...." >> $mysql_kill_timeout_log
echo `date` >> $mysql_kill_timeout_log
cat $mysql_kill_timeout_sh
Copy after login


把这个写到mysqld_kill_sleep.sh。然后chmod 0 mysqld_kill_sleep.sh,chmod u+rx mysqld_kill_sleep.sh,然后用root账户到cron里面运行即可,时间自己调整。

执行之后显示:


www# ./mysqld_kill_sleep.sh
/usr/local/bin/mysql -e "kill 27549" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27750" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27840" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27867" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27899" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27901" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27758" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27875" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27697" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27888" -uroot -p"mysql root的密码";
/usr/local/bin/mysql -e "kill 27861" -uroot -p"mysql root的密码";
Copy after login


如果确认没有问题了,把最后的cat修改为sh即可。

本人改写了下上面的脚本:


#!/bin/bash
mysql_pwd="密码"
mysql_exec="/usr/local/mysql/bin/mysql"
mysql_timeout_dir="/tmp"
mysql_kill_timeout_sh="$mysql_timeout_dir/mysql_kill_timeout.sh"
mysql_kill_timeout_log="$mysql_timeout_dir/mysql_kill_timeout.log"
$mysql_exec -uroot -p$mysql_pwd -e "show processlist" | grep -i "Locked" >> $mysql_kill_timeout_log
chmod 777 $mysql_kill_timeout_log
for line in `$mysql_kill_timeout_log | awk '{print $1}'`
do
echo "$mysql_exec -uroot -p$mysql_pwd -e \"kill $line\"" >> $mysql_kill_timeout_sh
done
chmod 777 $mysql_kill_timeout_sh
cat $mysql_kill_timeout_sh
Copy after login


 以上就是MYSQL锁表问题的解决方法_MySQL的内容,更多相关内容请关注PHP中文网(www.php.cn)!


Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template