What is the root operator in C language?
In the C language, there is no root operator. The built-in function "sqrt()" is used to open the root, and the syntax "sqrt (value x)" is used; for example, "sqrt(4)", Just perform the square root operation on 4, and the result is 2. sqrt() is a built-in root operation function in C language. Its operation result is the arithmetic square root of the function variable; this function can neither operate negative values nor output imaginary results.
The operating environment of this tutorial: windows7 system, c99 version, Dell G3 computer.
In the C language, there is no root operator. The built-in function "sqrt()" is used to open the root.
c language sqrt() function
In C language, sqrt means the square root function, which calculates the square root of a non-negative real number.
sqrt() is the built-in root operation function of C language, and its operation result is the arithmetic square root of the function variable.
The sqrt() function can neither operate on negative values nor output imaginary results.
Syntax:
double sqrt(double x)
Return value:
- ##This function returns the square root of x.
Usage of sqrt() function
Add #include#include<math.h>
#include<stdio.h>
int main(void)
{
printf("%lf",sqrt(4));
return 0;
}2.000000
Question:
Q1: "Is the type of the sqrt function parameter not a double-precision floating point type? Why is it mentioned above? In the example, the parameter of the sqrt function is an integer. Isn’t it a floating point number? Will there be any problems in passing parameters like this? "R1: It is necessary to answer this question here for the readers who raised this question: "To It is completely correct for the sqrt function to pass floating point numbers, and there is nothing wrong at all. Of course, there is no problem with passing an integer to the sqrt function, because passing an integer variable within the sqrt function will automatically be converted to a double precision floating point type. So can we How to avoid the process of converting parameters from integer to double-precision floating point? Of course. But we need to make a small modification to the above code:#include<math.h>
#include<stdio.h>
int main(void)
{
printf("%lf",sqrt(4.0));
return 0;
}| Input and output in the form of integer | |
| Input and output in the form of single-precision floating point | |
| Input and output in the form of double-precision floating point | |
| Input and output in the form of string Format input and output |
