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sde用sql实现erase_MySQL

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Release: 2016-05-27 16:57:02
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概述:

本文讲述基于Arc SDE forOracle实现erase空间分析计算。

实现流程:

\

 

1、叠加计算

判断叠加,非叠加部分即为一部分所要结果,叠加部分进入第二步;

2、合并计算

根据objectid进行union计算;

3、差异计算

用原始数据data1和合并计算后的结果进行差异计算,所得的结果即为另一部分所要结果。

 

相关sde函数介绍:

1、sde.st_intersection(st_geometryshape1, st_geometry shape2)

语法:

参数:(st_geometry shape1, st_geometryshape2)

返回值:st_geometry shape

解释:

Returns a geometry that represents the shared portion of shape1 andshape2.

示意:

\

 

 

2、sde.st_union(st_geometryshape1, st_geometry shape2)

语法:

参数:(st_geometry shape1, st_geometryshape2)

返回值:st_geometry shape

解释:

Returns a geometry that represents the point set union of theGeometries.

示意:

\

 

3、sde.st_difference(st_geometryshape1, st_geometry shape2)

语法:

参数:(st_geometry shape1, st_geometryshape2)

返回值:st_geometry shape

解释:

Returns a geometry thatrepresents that part of geometry A that does not intersect with geometry B.

示意:

\

 

说明:

看到图3,很多人就开始问了:erase的效果不就是图3的效果吗,为什么还要那么多步?是的,对于两两的geometry来说,difference结果即为我们想要的erase的结果,但是,对于两个图层来说,difference后的结果是整个data2的结果,并且结果中会有一些叠加与重复。为什么会出现这样的结果呢,我想sde的算法实现中,也是两两做的计算,因此,计算的结果就是整个data2的结果。举例:A为data1的一个要素,B、C分别为data2的两个要素,在sde中,difference计算的结果为图4,1和2分别为计算后的结果,并重叠在一起显示,但是实际中,我们想要的及全国是图5。

\
图4\
图5

实现sql实例:

1、计算叠加

insert intohx2q_risk_result_temp(objid,shape)
select *
from (select a.objectid,sde.st_intersection(a.shape, b.shape) as shape
from hx2q_project a, hx2q_landnormb
where a.ptcode = 'm01'
and b.ptcode = 'm01'
and a.status = '开工'
and b.confirm = '已取得'
and a.flag = 0
and b.flag = 0)
where sde.st_area(shape) > 0
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2、计算union

3、计算difference

insert intoHX2Q_RISK_RESULT
(objid, ptcode, Shape, objectid)
select a.objectid,
a.ptcode,
sde.st_difference(a.shape, b.shape) asshape,
SDE.version_user_ddl.NEXT_ROW_ID('HX2Q','36') as objectid
from hx2q_project a, hx2q_risk_result_temp b
where a.objectid = b.objid
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4、获取非叠加

insert intoHX2Q_RISK_RESULT
(objid, ptcode, Shape, objectid)
select objectid,
ptcode,
shape,
SDE.version_user_ddl.NEXT_ROW_ID('HX2Q','36')
from hx2q_project
where objectid not in (select distinct objidfrom hx2q_risk_result_temp)
and ptcode = 'm01' and flag = 0 and status = '开工'
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说明:

1、difference计算中,where后的条件是必须的;

2、union计算是通过后台程序实现的。

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