Let's talk about how to use PHP to convert data into JSON format

PHPz
Release: 2023-04-11 09:22:57
Original
1250 people have browsed it

In Internet applications, JSON (JavaScript Object Notation) is a commonly used data exchange format. In PHP development, converting PHP arrays to JSON format is a very common operation, because PHP arrays can easily handle large amounts of data, and the JSON format allows these data to be parsed, read, and stored by different programs and languages. . In this article, we will demonstrate through a simple example how to use PHP to convert data into JSON format.

1. Convert an array to a JSON string

Use the json_encode() function to convert a PHP array into a JSON format string. json_encode() The function can accept one or more parameters, where the first parameter is the PHP array to be converted. The following example demonstrates how to convert a simple PHP array to a JSON-formatted string:

$array = array(
    'name' => 'John Doe',
    'age' => 30,
    'email' => 'johndoe@example.com'
);

$json_data = json_encode($array);

echo $json_data;
// {"name":"John Doe","age":30,"email":"johndoe@example.com"}
Copy after login

In the above example, we first define an array containing three elements and use json_encode () function converts it into a string in JSON format. Finally, we print the string on the screen.

It should be noted that the json_encode() function will apply UTF-8 encoding format to the generated JSON string by default during conversion. If you need to use other encodings when converting, please refer to the documentation for this function.

2. Use JSON_PRETTY_PRINT to output JSON in beautified format

If you need to output the generated JSON string into beautified format with indentation and spaces, you can do it in json_encode() Use the JSON_PRETTY_PRINT parameter in the function. The example is as follows:

$array = array(
    'name' => 'John Doe',
    'age' => 30,
    'email' => 'johndoe@example.com'
);

$json_data = json_encode($array, JSON_PRETTY_PRINT);

echo $json_data;
/*
{
    "name": "John Doe",
    "age": 30,
    "email": "johndoe@example.com"
}
*/
Copy after login

3. Output JSON of Chinese character set

By default, the json_encode() function will convert the Chinese character set to Unicode encoding format, Causes the output JSON string to be difficult to read. You can use the JSON_UNESCAPED_UNICODE parameter to specify the output JSON of the Chinese character set. An example is as follows:

$array = array(
    'name' => '张三',
    'age' => 30,
    'email' => 'zhangsan@example.com'
);

$json_data = json_encode($array, JSON_UNESCAPED_UNICODE);

echo $json_data;
// {"name":"张三","age":30,"email":"zhangsan@example.com"}
Copy after login

In the above example, we used the JSON_UNESCAPED_UNICODE parameter to retain the original Chinese character set.

4. Parse a PHP array from a JSON string

We can also use the json_decode() function to parse a JSON-formatted string into a PHP array. The following example demonstrates how to re-convert the JSON string in the above example into a PHP array:

$json_data = '{"name":"John Doe","age":30,"email":"johndoe@example.com"}';

$array = json_decode($json_data, true);

print_r($array);
/*
Array
(
    [name] => John Doe
    [age] => 30
    [email] => johndoe@example.com
)
*/
Copy after login

It should be noted that the second parameter $assoc is an optional parameter. If Set it to true, the returned PHP data will be associative arrays (key-value pairs), otherwise if it is set to false, the returned PHP data will be objects.

5. Conclusion

In PHP development, data exchange using JSON format is very common. By using the json_encode() function, we can easily convert the PHP array into a JSON format string, and use the json_decode() function to convert the JSON format string into Reparse into a PHP array or object.

The above is the detailed content of Let's talk about how to use PHP to convert data into JSON format. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template