Table of Contents
为什么会产生 JSON 乱码?
如何解决 JSON 乱码?
方法二:使用 encoding/json
总结
Home Backend Development Golang Causes and solutions to JSON garbled characters in golang

Causes and solutions to JSON garbled characters in golang

Apr 11, 2023 am 10:42 AM

随着 Golang 的普及和应用范围的扩大,很多开发者常常会遇到一个令人头疼的问题:当将数据以 JSON 格式返回给客户端时,会出现中文乱码情况。本文将会介绍 Golang 中 JSON 乱码产生的原因以及如何解决该问题。

为什么会产生 JSON 乱码?

要解决问题,首先要了解产生问题的原因。在 Golang 中,当将数据以 JSON 格式返回给客户端时,有时候会出现中文乱码的情况。这是由于 Golang 默认采用了 UTF-8 编码,而 JSON 的编码方式是 UTF-8、UTF-16 或 UTF-32,不同的编码方式会导致乱码问题。

在使用 Golang 中处理 JSON 数据时,我们经常会使用 encoding/json 包进行编码和解码操作。默认情况下,encoding/json 包对输出的 JSON 数据采用 UTF-8 编码,但如果 JSON 数据中包含了非 UTF-8 编码的字符,就有可能导致乱码问题的出现。

在 Golang 中,中文字符通常使用 UTF-8 编码,但在其他编程语言中,可能使用 GBK、GB18030、UTF-16 等编码方式。当使用这些编码方式编码中文字符时,如果在 JSON 数据中输出这些中文字符,就会导致乱码问题的出现。

如何解决 JSON 乱码?

两种解决方法:

方法一:使用 json.RawMessage

json.RawMessage 是 Golang 中的一种特殊的数据类型,可以用于替代 interface{} 类型,可以用于存储原始 JSON 数据。使用 json.RawMessage 可以避免 JSON 输出中的乱码问题,具体方法如下:

type User struct {
    Name string          `json:"name"`
    Age  int             `json:"age"`
    Info json.RawMessage `json:"info"`
}

func main() {
    user := User{
        Name: "张三",
        Age:  18,
        Info: []byte(`{"address":"北京市"}`),
    }
    data, err := json.Marshal(user)
    if err != nil {
        fmt.Println("json encode err:", err)
        return
    }
    fmt.Println(string(data))
}
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在上述代码中,我们使用了 json.RawMessage 存储 JSON 数据,避免了中文字符的乱码问题。

方法二:使用 encoding/json

在 Golang 中,可以通过修改 encoding/json 包的 Marshal 函数来解决 JSON 乱码问题。具体方法如下:

func main() {
    user := User{
        Name: "张三",
        Age:  18,
        Info: map[string]interface{}{
            "address": "北京市",
        },
    }
    data, err := MarshalWithUTF8(user)
    if err != nil {
        fmt.Println("json encode err:", err)
        return
    }
    fmt.Println(string(data))
}

func MarshalWithUTF8(v interface{}) ([]byte, error) {
    data, err := json.Marshal(v)
    if err != nil {
        return nil, err
    }
    return []byte(strings.Replace(string(data), "\\u0026", "&", -1)), nil
}
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在上述代码中,我们修改了 Marshal 函数的返回值并进行了替换操作,避免了中文字符的乱码问题。

总结

JSON 乱码是 Golang 开发中遇到的一个令人头疼的问题,但是通过使用 json.RawMessage 或修改 encoding/json 包的 Marshal 函数、替换操作,我们可以避免这个问题的出现,保证数据的完整性和准确性,提高代码的稳定性和可靠性。

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