How to implement mahjong and card programs in java

The following is a mahjong and tiles program written in Java:

public class MaJiang2
{
private boolean jiang=false;//是否找到将
public MaJiang2(){}
//花色，判断这个花色是否被减完了（如果没有减完自然没有和）
private int huase(int[] hua)
{
if (hua.length==7)
{
//判断字，自比较特殊，没有顺
for (int i=0;i<HUA.LENGTH ;i++ )
{
if (hua[i]==3||hua[i]==4)
{
hua[i]=0;
huase(hua);
}
//如果字有两个，肯定是将
if (hua[i]==2&&!jiang)
{
hua[i]=0;
jiang=true;
huase(hua);
}
}
}
else
{
for (int i=0;i<HUA.LENGTH ;i++ )
{
//如果没有将，先把将减出去
if (!jiang&&hua[i]>=2)
{
hua[i]=hua[i]-2;
jiang=true;
int fanhui=huase(hua);
//如果递归回来依旧没有减完，则把将加回去
if (fanhui!=0)
{
hua[i]=hua[i]+2;
jiang=false;
}
}
if (hua[i]!=0&&i<7&&hua[i+1]!=0&&hua[i+2]!=0)
{
hua[i]--;
hua[i+1]--;
hua[i+2]--;
huase(hua);
int fanhui=huase(hua);
//如果递归回来依旧没有减完，减去的加回去
if (fanhui!=0)
{
hua[i]++;
hua[i+1]++;
hua[i+2]++;
}
}
if (hua[i]==3||hua[i]==4)
{
int temp=hua[i];
hua[i]=0;
huase(hua);
int fanhui=huase(hua);
//如果递归回来依旧没有减完，减去的加回去
if (fanhui!=0)
{
hua[i]++;
hua[i]=temp;
}
}
}
}
int re=0;
//最后判断减没减完
for (int i=0;i<HUA.LENGTH ;i++ )
{
re=re+hua[i];
}
return re;
}
public void Hu(int[] aWan,int[] aTiao,int[] aTong,int[] aZi)
{
//先从字开始，如果某一花色计算完之后依旧不为0，则肯定不和。如果所有的花色全部减完了，就和了，呵呵：-〉
int jieguo=huase(aZi);
if (jieguo!=0)
{
System.out.println("没和");
}
else if ((jieguo=huase(aWan))!=0)
{
System.out.println("没和");
}
else if ((jieguo=huase(aTiao))!=0)
{
System.out.println("没和");
}
else if ((jieguo=huase(aTong))!=0)
{
System.out.println("没和");
}
else
{
System.out.println("和了，真不容易，一脑门子汉");
}
}
public static void main(String[] args) 
{
MaJiang2 mj=new MaJiang2();
int[] w={3,1,1,2,1,1,1,1,3};
int[] ti={0,0,0,0,0,0,0,0,0};
int[] to={0,0,0,0,0,0,0,0,0};
int[] z={0,0,0,0,0,0,0};
mj.Hu(w,ti,to,z);
}
}

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