Vue is a popular front-end framework that uses a component-based approach to build applications. Vue router is a plug-in provided by Vue that can easily divide the application into multiple views and allow users to navigate between views. In Vue router, each view is a route, and each route can have multiple sub-routes. This article will introduce how to jump sub-routes.
Declaring sub-routes in Vue router requires the use of nested routes. Use the children field in the parent route to declare child routes. For example:
const router = new VueRouter({ routes: [ { path: '/parent', component: Parent, children: [ { path: 'child', component: Child } ] } ] })
In the above code, we declare a parent route named parent, and a child route named child. When the user accesses /parent/child, the Parent and Child components will be rendered.
Jump routing in Vue can use the router-link component or programmatic navigation of the $router object. When jumping sub-routes, we need to provide the complete routing path. For example, to jump to the child route in the above example, we need to provide the full route path of /parent/child.
Use router-link:
<router-link to="/parent/child">跳转到子路由</router-link>
Use programmatic navigation:
this.$router.push('/parent/child')
In the above code, we use the $router.push method to jump routes.
In practice, we often need to jump to sub-routes and pass some parameters. In Vue, we can pass parameters using the params field in programmatic navigation. For example:
this.$router.push({ path: '/parent/child', params: { id: 1 }})
In the above code, we passed an id parameter with a value of 1. In the sub-routing component that receives parameters, we can get the parameters through this.$route.params.
export default { mounted() { console.log(this.$route.params.id) // 输出1 } }
This article introduces how to jump sub-routes in Vue routing. We covered how to declare subroutes, how to use router-link and programmatic navigation to jump to subroutes, and how to pass parameters. Hope this article is helpful to beginners.
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