1. Background introduction
With the continuous development of Internet technology, more and more Web applications need to support the image upload function. Uniapp is a very popular mobile development framework, which is cross-platform, efficient, and easy to use. However, when we use uniapp to develop the multi-image upload function, we will encounter some problems: the server cannot correctly receive the request and cannot obtain the passed image information. This article will explore possible causes and solutions to this problem.
2. Problem description
We use the upload component plug-in provided by uniappuni-upload
to develop the multi-image upload function and use PHP back-end code to receive upload requests and save image information. The upload page code is as follows:
<template> <view class="container"> <view class="uploadBtn" @tap="chooseImage"> <image src="../../static/plus.png"></image> </view> <view class="image-list"> <view class="image-item" v-for="(item, index) in fileList" :key="index"> <image :src="item.path"></image> <view class="delete" @tap="deleteImage(index)">删除</view> </view> </view> <view class="submitBtn" @tap="submit"> 提交 </view> </view> </template> <script> import uniUpload from "@/components/uni-upload/uni-upload.vue"; export default { components: { uniUpload }, data() { return { fileList: [], }; }, methods: { chooseImage() { uni.chooseImage({ count: 9, success: (res) => { this.fileList = [...this.fileList, ...res.tempFilePaths.map((path) => ({ path }))]; }, }); }, deleteImage(index) { this.fileList.splice(index, 1); }, submit() { const formData = new FormData(); this.fileList.forEach((item, index) => { formData.append(`file${index}`, item.path); }); uni.request({ method: "POST", url: "http://localhost/upload.php", header: { "Content-Type": "multipart/form-data", }, data: formData, success: (res) => { console.log("upload success", res.data); }, fail: (error) => { console.log("upload fail", error); }, }); }, }, }; </script>
The upload component uses the uni-upload
plug-in, which calls the album to select pictures through the chooseImage
method, and adds tempFilePaths
to Fill in the image path in fileList
, and upload the image path in fileList
to the backend server in the submit
method.
On the server side, we use PHP as the back-end language, the code is as follows:
<?php $upload_dir = "uploads/"; if (!file_exists($upload_dir)) { mkdir($upload_dir); } foreach ($_FILES as $key => $file) { $tmp_name = $file["tmp_name"]; $name = $file["name"]; if (move_uploaded_file($tmp_name, $upload_dir . $name)) { echo "upload success "; } else { echo "upload fail "; } } ?>
It was found in the local test that after submitting the image, the back-end server could not correctly read the upload request and could not Save pictures correctly. Some solutions will be proposed below.
3. Cause of the problem
According to the error message, it may be caused by incorrect file upload method. FormData and multipart/form-data are now an important way to implement file upload through forms. However, if the appropriate request header information is not set, the server cannot correctly obtain the uploaded file, which may be the cause of this problem.
4. Solution
Add the header content type and boundary in the upload request, where type is when sending the request The boundary part of the Content-Type is a random string that splits the data.
uni.request({
method: "POST",
url: "http://localhost/upload.php",
header: {
"Content-Type": "multipart/form-data; boundary=" + Math.random().toString().substr(2),
},
data: formData,
success: (res) => {
console.log("upload success", res.data);
},
fail: (error) => {
console.log("upload fail", error);
} ,
});
On the client, we assemble the file list into formData through form data append. At this time, the key of each file defaults to its position in formData, which is an increasing number starting from 0. The key received by the server may be the name
value specified in the upload component. Therefore, when uploading files, you can specify a key name for each file, as follows:
this.fileList. forEach((item, index) => {
formData.append("file" index, item.path);
});
Because of the file
here It is different from the name
attribute value of the uploaded component, so it should also be modified accordingly during back-end processing.
foreach($_FILES as $file) {
$tmp_name = $file["tmp_name"];
$name = $file["name"];
if (move_uploaded_file( $tmp_name, $upload_dir . $name)) {
echo "upload success ";
} else {
echo "upload fail ";
}
}
For higher versions of PHP, you need to add the following parameters to the php.ini
file:
post_max_size=20M
upload_max_filesize=20M
max_execution_time=600
max_input_time=600
After the setting is completed, Apache needs to be restarted to take effect.
4. Summary
This article discusses the problem that the image information transmitted when uploading multiple images in uniapp cannot be received by PHP. By modifying the request header information, changing the key name of the uploaded file and configuring PHP .ini file, etc., successfully solved the problem. Finally, it is recommended that web developers pay attention to effective testing of the upload function when using uniapp for mobile application development to reduce unnecessary errors and losses.
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