Home Backend Development PHP Problem How to determine if there is an element in an array in php

How to determine if there is an element in an array in php

Apr 23, 2023 am 09:10 AM

In PHP, determining whether an element exists in an array is a basic operation. We can use a variety of methods to achieve this functionality. This article will introduce several commonly used methods to determine whether an element exists in a PHP array.

Method 1: Use the in_array() function

The in_array() function can determine whether a value exists in the array. This function searches the array for the specified value and returns a Boolean value of true or false. It takes two parameters, the first parameter is the value to find and the second parameter is the array.

Sample code:

$array = array('apple', 'banana', 'orange');

if (in_array('banana', $array)) {
    echo 'banana 存在于该数组中';
} else {
    echo 'banana 不存在于该数组中';
}
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Output result:

banana 存在于该数组中
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Method 2: Use the array_search() function

array_search() function to search for the specified value in the array value, and returns the key name of the value (that is, the array subscript). If the value does not exist, returns false.

Sample code:

$array = array('apple', 'banana', 'orange');

$index = array_search('banana', $array);

if ($index !== false) {
    echo 'banana 存在于该数组中,其下标为:' . $index;
} else {
    echo 'banana 不存在于该数组中';
}
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Output result:

banana 存在于该数组中,其下标为:1
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Method 3: Use isset() function

isset() function is used to detect whether the variable has been Set and not null. In PHP, when the value of an array element is null, it is invalid to use the isset() function to determine whether an element exists in the array.

Sample code:

$array = array('apple', 'banana', 'orange', null);

if (isset($array[3])) {
    echo '数组 $array 中存在下标为 3 的元素';
} else {
    echo '数组 $array 中不存在下标为 3 的元素';
}
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Output result:

数组 $array 中存在下标为 3 的元素
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Method 4: Use array_key_exists() function

array_key_exists() function is used to check the given Whether the key name or index exists in the array. Returns true if the specified key or index exists, false otherwise.

Sample code:

$array = array('apple', 'banana', 'orange', null);

if (array_key_exists(3, $array)) {
    echo '数组 $array 中存在下标为 3 的元素';
} else {
    echo '数组 $array 中不存在下标为 3 的元素';
}
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Output result:

数组 $array 中存在下标为 3 的元素
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Summary:

The above four methods can be used to determine whether a certain object exists in the PHP array element. Among them, the in_array() function and array_search() function are suitable for finding values, while the isset() function and array_key_exists() function are suitable for finding key names or indexes. Which method to choose depends on actual needs.

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