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Thinkphp+smarty+uploadify实现无刷新上传_PHP

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Release: 2016-05-30 08:47:34
Original
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本文实例讲述了Thinkphp+smarty+uploadify实现无刷新上传的方法。分享给大家供大家参考。具体如下:

模板文件代码:

<!DOCTYPE html>
<html lang="cn">
 <head>
  <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
  <link href="<{$smarty.const.PUBLIC_PATH}>/Uploadify/uploadify.css" rel="stylesheet" type="text/css" />
  <script src="<{$smarty.const.PUBLIC_PATH}>/Uploadify/jquery.js" type="text/javascript"></script>
  <script src="<{$smarty.const.PUBLIC_PATH}>/Uploadify/jquery.uploadify.min.js" type="text/javascript"></script>
 </head>
 <script type="text/javascript">
  $(function() {
   $("#file_upload").uploadify({
    //指定swf文件
    'swf': '<{$smarty.const.PUBLIC_PATH}>/Uploadify/uploadify.swf',
    //后台处理的页面
    'uploader': "<{U('home/Login/Uploads','',false)}>",
    //按钮显示的文字
    'buttonText': '上传图片',
     //显示的高度和宽度
    "height" : 30,
    'fileTypeDesc': 'Image Files',
    //允许上传的文件后缀
    'fileTypeExts': '*.gif; *.jpg; *.png',
    //发送给后台的其他参数通过formData指定
    //'formData': { 'someKey': 'someValue', 'someOtherKey': 1 },
    "method" : 'post',//方法,服务端可以用$_POST数组获取数据
    'removeTimeout'  : 1,
    "onUploadSuccess" : uploadPicture
  });
  //可以根据自己的要求来做相应处理
  function uploadPicture(file, data){
    var data = eval('(' + data + ')');
   if(data.errorcode){
    alert(data.errormsg); 
   } else {
    alert(data.errormsg);
   }
  } 
 });
</script>
 <body>
  <input type="file" name="file_upload" id="file_upload" />
 </body>
</html>

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控制器代码:

public function uploads(){
  $arr = array( "errorcode"=>"1","errormsg"=>"上传成功!");
  $model = M('applicant');
  if (!empty($_FILES)) {
    //图片上传设置
    $config = array( 
    'maxSize' => 1000000, 
    'rootPath' => 'Public',
    'savePath' => '/Uploads/', 
    'saveName' => array('uniqid',''), 
    'exts'  => array('jpg', 'gif', 'png', 'jpeg'), 
    'autoSub' => false, 
    'subName' => array('date','Ymd'),
   );
   $upload = new \Think\Upload($config);// 实例化上传类
  $info = $upload->upload();
   if($info){
    $arr['errorcode'] = "0";
   } else {
    $arr["errorcode"] = "1";
    $arr["errormsg"] = $upload->getError();
   }
   /* 返回JSON数据 */
   $this->ajaxReturn($arr);
  }
}

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希望本文所述对大家的php程序设计有所帮助。

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