How to use java method reference

1. Description

Method reference can be regarded as the deep expression of Lambda expression. In other words, a method reference is a Lambda expression, an example of a functional interface, that points to a method by its name.

2. Usage scenarios

When the operation to be passed to the Lambda body has been implemented, you can use the method reference

3. Format

类(或对象) :: 方法名

4. Example

public class MethodRefTest {

    // 情况一：对象 :: 实例方法
    //Consumer中的void accept(T t)
    //PrintStream中的void println(T t)
    @Test
    public void test1() {
        //使用Lambda表达
        Consumer<String> con1 = str -> System.out.println(str);
        con1.accept("中国");
        System.out.println("====================");

        //使用方法引用
        PrintStream ps = System.out;
        Consumer con2 = ps::println;
        con2.accept("China");

    }

    //Supplier中的T get()
    //Employee中的String getName()
    @Test
    public void test2() {
        //使用Lambda表达
        Employee emp = new Employee(1001, "Bruce", 34, 600);
        Supplier<String> sup1 = () -> emp.getName();
        System.out.println(sup1.get());
        System.out.println("====================");

        //使用方法引用
        Supplier sup2 = emp::getName;
        System.out.println(sup2.get());


    }

    // 情况二：类 :: 静态方法
    //Comparator中的int compare(T t1,T t2)
    //Integer中的int compare(T t1,T t2)
    @Test
    public void test3() {
        //使用Lambda表达
        Comparator<Integer> com1 = (t1, t2) -> Integer.compare(t1, t2);
        System.out.println(com1.compare(32, 45));
        System.out.println("====================");

        //使用方法引用
        Comparator<Integer> com2 = Integer::compareTo;
        System.out.println(com2.compare(43, 34));
    }

    //Function中的R apply(T t)
    //Math中的Long round(Double d)
    @Test
    public void test4() {
        //使用匿名内部类
        Function<Double, Long> func = new Function<Double, Long>() {
            @Override
            public Long apply(Double aDouble) {
                return Math.round(aDouble);
            }
        };
        System.out.println(func.apply(10.5));
        System.out.println("====================");

        //使用Lambda表达式
        Function<Double, Long> func1 = d -> Math.round(d);
        System.out.println(func1.apply(12.3));
        System.out.println("====================");

        //使用方法引用
        Function<Double, Long> func2 = Math::round;
        System.out.println(func2.apply(12.6));


    }

    // 情况三：类 :: 实例方法
    // Comparator中的int comapre(T t1,T t2)
    // String中的int t1.compareTo(t2)
    @Test
    public void test5() {
        //使用Lambda表达式
        Comparator<String> com1 = (s1, s2) -> s1.compareTo(s2);
        System.out.println(com1.compare("abd", "aba"));
        System.out.println("====================");

        //使用方法引用
        Comparator<String> com2 = String::compareTo;
        System.out.println(com2.compare("abd", "abc"));
    }

    //BiPredicate中的boolean test(T t1, T t2);
    //String中的boolean t1.equals(t2)
    @Test
    public void test6() {
        //使用Lambda表达式
        BiPredicate<String, String> pre1 = (s1, s2) -> s1.equals(s2);
        System.out.println(pre1.test("abc", "abc"));
        System.out.println("====================");

        //使用方法引用
        BiPredicate<String, String> pre2 = String::equals;
        System.out.println(pre2.test("abc", "abd"));

    }

    // Function中的R apply(T t)
    // Employee中的String getName();
    @Test
    public void test7() {
        //使用Lambda表达式
        Employee employee = new Employee(1001, "Tom", 45, 10000);

        Function<Employee, String> func1 =e->e.getName();
        System.out.println(func1.apply(employee));
        System.out.println("====================");

        //使用方法引用
        Function<Employee,String>func2 = Employee::getName;
        System.out.println(func2.apply(employee));
    }
}

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