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Mysql获取成绩排序后的名次_MySQL

WBOY
Release: 2016-05-30 17:11:14
Original
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其实就是输出mysql的排序后的行号
RT:获取单个用户的成绩在所有用户成绩中的排名
可以分两步: 1、查出所有用户和他们的成绩排名

select id,maxScore,(@rowNum:=@rowNum+1) as rowNo
from t_user,
(select (@rowNum :=0) ) b
order by t_user.maxScore desc 
Copy after login

2、查出某个用户在所有用户成绩中的排名
select u.rowNo from (
select id,(@rowNum:=@rowNum+1) as rowNo
from t_user,
(select (@rowNum :=0) ) b
order by t_user.maxScore desc ) u where u.id="2015091810371700001";
Copy after login

OK~ 一切搞定

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