php insert successful data is not displayed

In PHP development, database operations are often involved, and the most common operation is to insert data. The implementation process of the insertion operation is relatively simple, but in actual development, various problems often occur. For example, after inserting data, the page does not display the successful insertion information in real time. In this case, we need to troubleshoot the problem from the following aspects.

1. Check code logic

First of all, you need to check whether there is any problem with your code logic. When performing an insert operation, data verification is often performed first, and then the insert operation is performed. If an error occurs during data verification, the insertion operation will not be performed correctly. Therefore, the code logic needs to be carefully checked to ensure that nothing is omitted.

2. Check database connection

When performing an insert operation, a connection must be established with the database. If the connection is wrong, then the insert operation cannot be performed. Therefore, you need to ensure that the database connection is correct. Normally, you can use code similar to the following to establish a connection:

$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}

Where $servername represents the server name, $username represents the user name, $password represents the password, and $dbname represents the database name. If the connection fails, "Connection failed: " will be output and an error message will be displayed.

3. Check sql statement

When inserting, you need to use sql statement to execute. If there is a problem with the sql statement, the insert operation cannot be executed. Common problems include spelling errors in SQL statements, missing keywords, grammatical errors, etc. Therefore, you need to carefully check whether the sql statement is correct. Normally, you can use code similar to the following to execute a sql statement:

$sql = "INSERT INTO MyGuests (firstname, lastname, email) VALUES ('John', 'Doe', 'john@example.com')";
if (mysqli_query($conn, $sql)) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

Among them, $sql represents the sql statement to be executed. If the execution is successful, "New record created successfully" will be output. If the execution fails, it will Output "Error: " and display the error message.

4. Check the page output

Finally, probably the most common problem is that the page does not correctly output the insertion success information. In this case, you need to carefully check your code for problems. Normally, you can use the following method to output information about successful insertion:

if (mysqli_query($conn, $sql)) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}

Among them, if the insertion is successful, "New record created successfully" will be output. If the insertion fails, relevant error information will be output. If your page does not correctly output the insertion success information, it is recommended that you carefully check your code, especially the output part of the code. There may be some details that you have overlooked.

Summary:

In the process of PHP development, inserting data is one of the most commonly used and basic operations. However, it is a major difficulty that the insertion is successful but fails to output. You may need to Check your code logic, check the database connection, check the SQL statement, and check the page output issues. If you encounter the problem of successfully inserted data not being displayed, I hope this article can help you.

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