How to implement softmax backpropagation in Python.

WBOY
Release: 2023-05-09 08:05:53
forward
1211 people have browsed it

Backpropagation derivation

As you can see, softmax calculates the inputs of multiple neurons. When deriving backpropagation, you need to consider deriving the parameters of different neurons.

Consider two situations:

  • When the parameter for derivation is located in the numerator

  • When the parameter for derivation is located at When the denominator is

How to implement softmax backpropagation in Python.

When the parameter for derivation is in the numerator:

How to implement softmax backpropagation in Python.

When derivation When the parameter is in the denominator (ez2 or ez3 are symmetrical, the derivation results are the same):

How to implement softmax backpropagation in Python.

How to implement softmax backpropagation in Python.

code

import torch
import math

def my_softmax(features):
    _sum = 0
    for i in features:
        _sum += math.e ** i
    return torch.Tensor([ math.e ** i / _sum for i in features ])

def my_softmax_grad(outputs):    
    n = len(outputs)
    grad = []
    for i in range(n):
        temp = []
        for j in range(n):
            if i == j:
                temp.append(outputs[i] * (1- outputs[i]))
            else:
                temp.append(-outputs[j] * outputs[i])
        grad.append(torch.Tensor(temp))
    return grad

if __name__ == '__main__':

    features = torch.randn(10)
    features.requires_grad_()

    torch_softmax = torch.nn.functional.softmax
    p1 = torch_softmax(features,dim=0)
    p2 = my_softmax(features)
    print(torch.allclose(p1,p2))
    
    n = len(p1)
    p2_grad = my_softmax_grad(p2)
    for i in range(n):
        p1_grad = torch.autograd.grad(p1[i],features, retain_graph=True)
        print(torch.allclose(p1_grad[0], p2_grad[i]))
Copy after login

The above is the detailed content of How to implement softmax backpropagation in Python.. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:yisu.com
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template