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MySQL 删除数据库中重复数据(以部分数据为准)_MySQL

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Release: 2016-05-31 08:47:43
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delete from zqzrdp

where tel  in (select min(dpxx_id) from  zqzrdp  group by tel  having count(tel)>1);

执行,报错

异常意为:你不能指定目标表的更新在FROM子句。傻了,MySQL 这样写,不行,让人郁闷。

难倒只能分步操作,蛋疼

以下是网友写的,同样是坑爹的代码,我机器上运行不了。

1. 查询需要删除的记录,会保留一条记录。

代码如下 复制代码

select a.id,a.subject,a.RECEIVER from test1 a left join (select c.subject,c.RECEIVER ,max(c.id) as  bid from test1 c where status=0 GROUP BY RECEIVER,SUBJECT having count(1) >1) b on a.id

2. 删除重复记录,只保留一条记录。注意,subject,RECEIVER 要索引,否则会很慢的。

代码如下 复制代码

delete a from test1 a, (select c.subject,c.RECEIVER ,max(c.id) as  bid from test1 c where status=0 GROUP BY RECEIVER,SUBJECT having count(1) >1) b where a.subject=b.subject and a.RECEIVER = b.RECEIVER and a.id

3. 查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断

代码如下 复制代码

select * from people where peopleId in (select  peopleId  from  people  group  by  peopleId  having  count(peopleId) > 1)

4. 删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录

代码如下 复制代码

delete from people

where peopleId  in (select  peopleId  from people  group  by  peopleId   having  count(peopleId) > 1)

and rowid not in (select min(rowid) from  people  group by peopleId  having count(peopleId )>1)

5.删除表中多余的重复记录(多个字段),只留有rowid最小的记录

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