golang uint to byte

During the development process of Golang, we often need to convert integer types to byte (byte) types for transmission and storage as byte arrays. Among them, the uint type is one of the most commonly used integer types. Therefore, it is very important for Golang developers to master the method of converting uint type to bytes. This article will briefly introduce how to convert uint type to byte type in golang.

1. Convert uint to byte type

First, we need to understand the underlying storage methods of uint type and byte type. In Golang, the uint type is an unsigned integer, occupying 8 bytes of memory space; and the byte type is an alias type, essentially an unsigned 8-bit integer type. Therefore, to convert the uint type to the byte type, you need to intercept the lower 8 bits of the uint type, that is, convert the uint type to an 8-bit byte type.

In Golang, you can convert uint type to byte type through type assertion. The specific method is as follows:

var n uint64 = 256
var b byte
b = byte(n)
fmt.Println(b) // 输出 0

In the above code, variable n represents the uint type value to be converted, and variable b represents the converted byte type value. In the third line of code, use byte(n) for type assertion and convert n to byte type. Since the value of n is 256, which is 100000000 in binary, it exceeds the value range of the byte type (the value range of the byte type is 0~255), so only the lower 8 bits of n are taken, and the result is 0.

It should be noted that the uint type can be any unsigned integer type, such as uint8, uint16, uint32, uint64. When converting uint type to byte type, you need to cast it to uint8 type and then perform type assertion. The specific code is as follows:

var n uint16 = 256
var b byte
b = uint8(n)
fmt.Println(b) // 输出 0

In the above code, the variable n is of uint16 type. Since it needs to be converted to byte type, it needs to be cast to uint8 type first, and then type assertion is performed.

2. Example Demonstration

Below, I will demonstrate a practical example to show how to convert uint type to byte type.

package mainimport (    "fmt"    "encoding/binary")func main() {    var n uint16 = 258    var b [2]byte    binary.LittleEndian.PutUint16(b[:], n)    fmt.Println(b) // 输出 [2 1]}

In the above code, the variable n is of uint16 type and the value is 258. Variable b is a byte array of length 2, used to store converted byte data. In the fourth line of code, the binary.LittleEndian.PutUint16() function is used to convert the Uint16 type data n into byte type data, and the result is saved in the array b. The first parameter b[:] represents all elements of the byte array. Here, we use little-endian for byte serialization, that is, the low byte is stored in the front and the high byte is stored in the back. Since the binary representation of 258 is 0000000100000010, the low byte is 00000010, and the high byte is 00000001, the converted result is [2,1].

3. Summary

Through the above introduction, we learned about the method of converting uint type to byte type in Golang. In the actual development process, we often need to transmit and store byte-level data, so mastering this method is very useful. It should be noted that when performing type conversion, byte order must be taken into consideration to avoid errors during data transmission and storage.

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