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php实现Mongodb自定义方式生成自增ID的方法_PHP

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Release: 2016-05-31 11:45:36
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本文实例讲述了php实现Mongodb自定义方式生成自增ID的方法。分享给大家供大家参考。具体分析如下:

代码如下:

//首先创建一个自动增长id集合 ids
>db.ids.save({name:"user", id:0});
//可以查看一下是否成功
> db.ids.find();
{ "_id" : ObjectId("4c637dbd900f00000000686c"), "name" : "user", "id" : 0 }
//然后每次添加新用户之前自增一下 ids集合 获得id
>userid = db.ids.findAndModify({update:{$inc:{'id':1}}, query:{"name":"user"}, new:true});
{ "_id" : ObjectId("4c637dbd900f00000000686c"), "name" : "user", "id" : 1 }
//注:因为findAndModify是一个方法完成更新查找两个操作,所以具有原子性,多线程不会冲突。
//然后保存相应的数据
>db.user.save({uid:userid.id, username:"kekeles", password:"kekeles", info:"http://www.jb51.net/ "});
//查看结果
> db.user.find();
{ "_id" : ObjectId("4c637f79900f00000000686d"), "uid" : 1, "username" : "admin", "password" : "admin" }
//这是mongo的shell,如果用的是服务器端程序java php python,可以自己对这些操作封装一下,只用传几个参数就可以返回自增的id,还可以实现像Oracle的跨表的自增id。

自己写了一段php的,拿出来给大家分享。

<&#63;php
function mid($name, $db){
$update = array('$inc'=>array("id"=>1));
$query = array('name'=>$name);
$command = array(
'findandmodify'=>'ids', 'update'=>$update,
'query'=>$query, 'new'=>true, 'upsert'=>true
);
$id = $db->command($command);
return $id['value']['id'];
}
$conn = new Mongo();
$db = $conn->idtest;
$id = mid('user', $db);
$db->user->save(array(
'uid'=>$id, 
'username'=>'kekeles', 
'password'=>'kekeles',
 'info'=>'http://www.jb51.net/ '
));
$conn->close();
&#63;>
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希望本文所述对大家的php程序设计有所帮助。

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