How to split words and convert naming in Python

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Release: 2023-05-13 12:31:06
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分割单词

将一个标识符分割成若干单词存进列表,便于后续命名法的转换

先引入正则表达式包

import re
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至于如何分割单词看个人喜好,如以常见分隔符 “ ”、“_”、“-”、“/”、“\” 去分割

re.split('[ _\-/\\\\]+', name)
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还可以范围再广一点,拿除了数字和字母以外的所有字符去分割

re.split('[^0-9a-zA-Z]', name)
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那对于字母内部怎么分割呢?

综合考虑驼峰命名法、连续大写的缩写单词等,笔者根据经验一般会采用这种策略,连续比较三个字符,满足以下条件之一就分割:“小|大无”、“有|大小”、“小|大有”

  • 是尾字符,是大写,倒数第二个字符是小写,在尾字符前分割,比如 'getA' 分割成 ['get','A']

  • 是非首位的中间字符,是大写,前后至少有一个是小写,在该字符前分割,比如 'getJSONString' 分割成 ['get','JSON','String']

对于字母和数字结合的标识符,就比较难处理了

因为有的数字可以作为单词开头(比如 '3D'),有的又可以作为结尾(比如 'HTML5'),还有的字母数字交错(比如 'm3u8'),暂未想到通用的分割的好办法,根据个人需求实现就行了

综合以上几者的分割函数如下

def to_words(name):
    words = []                  # 用于存储单词的列表
    word = ''                   # 用于存储正在构建的单词

    if(len(name) <= 1):
        words.append(name)
        return words

    # 按照常见分隔符进行分割
    # name_parts = re.split(&#39;[ _\-/\\\\]+&#39;, name)
    # 按照非数字字母字符进行分割
    name_parts = re.split(&#39;[^0-9a-zA-Z]&#39;, name)
    for part in name_parts:
        part_len = len(part)        # 字符串的长度
        word = ''
        # 如果子串为空,继续循环
        if not part:
            continue   
        for index, char in enumerate(part):
            # “小|大无”
            if(index == part_len - 1):
                if(char.isupper() and part[index-1].islower()):
                    if(word): words.append(word)
                    words.append(char)
                    word = ''
                    continue

            # “有|大小”或“小|大有”
            elif(index != 0 and char.isupper()):
                if((part[index-1].islower() and part[index+1].isalpha()) or (part[index-1].isalpha() and part[index+1].islower())):
                    if(word): words.append(word)
                    word = ''
            word += char
        if(len(word) > 0): words.append(word)
    # 去除空单词
    return [word for word in words if word != '']
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测试用例如下

print(to_words(&#39;IDCard&#39;)) # [&#39;ID&#39;, &#39;Card&#39;]
print(to_words(&#39;getJSONObject&#39;)) # [&#39;get&#39;, &#39;JSON&#39;, &#39;Object&#39;]
print(to_words(&#39;aaa@bbb.com&#39;)) # [&#39;aaa&#39;, &#39;bbb&#39;, &#39;com&#39;]
print(to_words(&#39;D://documents/data.txt&#39;)) # [&#39;D&#39;, &#39;documents&#39;, &#39;data&#39;, &#39;txt&#39;]
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分割成全小写单词

def to_lower_words(name):
    words = to_words(name)
    return [word.lower() for word in words]
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分割成全大写单词

def to_upper_words(name):
    words = to_words(name)
    return [word.upper() for word in words]
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分割成首大写、其余小写单词

def to_capital_words(name):
    words = to_words(name)
    return [word.capitalize() for word in words]
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转中划线命名法

中划线命名法,也叫烤肉串命名法(kebab case),如 'kebab-case'

  • 字母全小写

  • 连字符连接

def to_kebab_case(name):
    words = to_lower_words(name)
    to_kebab_case = &#39;-&#39;.join(words)
    return to_kebab_case
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转小蛇式命名法

小蛇式命名法,其实就是小写下划线命名法,也叫蛇式命名法(snake case),如 'snake_case'

  • 字母全小写

  • 下划线连接

def to_snake_case(name):
    words = to_lower_words(name)
    snake_case_name = &#39;_&#39;.join(words)
    return snake_case_name
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转大蛇式命名法

大蛇式命名法,其实就是大写下划线命名法,也叫宏命名法(macro case),如 'MACRO_CASE'

  • 字母全大写

  • 下划线连接

def to_macro_case(name):
    words = to_upper_words(name)
    snake_case_name = &#39;_&#39;.join(words)
    return snake_case_name
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转小驼峰命名法

小驼峰命名法,也叫驼峰命名法(camel case) ,如 'camelCase'

  • 首单词首字母小写,后每个单词首字母大写

  • 不使用连接符

def to_camel_case(name):
    words = to_words(name)
    camel_case_words = []
    for word in words:
        if len(word) <= 1:
            camel_case_words.append(word.upper())
        else:
            camel_case_words.append(word[0].upper() + word[1:])

    camel_case = &#39;&#39;.join(camel_case_words)
    if len(camel_case) <= 1:
        camel_case = camel_case.lower()
    else:
        camel_case = &#39;&#39;.join(camel_case[0].lower() + camel_case[1:])
    return camel_case
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转大驼峰命名法

大驼峰命名法,也叫帕斯卡命名法(pascal case) ,如 'PascalCase'

  • 每个单词首字母大写

  • 不使用连接符

def to_pascal_case(name):
    words = to_words(name)
    pascal_case_words = []
    for word in words:
        if len(word) <= 1:
            pascal_case_words.append(word.upper())
        else:
            pascal_case_words.append(word[0].upper() + word[1:])
    pascal_case = &#39;&#39;.join(pascal_case_words)
    return pascal_case
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