How to use streams to sort arrays in java

1. Sorting ideas

(1) Read text from the character input stream and buffer each character to achieve efficient reading of characters, arrays and lines

(2) Ask the user how many digits the array requires

(3) Convert to numeric type

(4) Store the user input number into the array

(5 ) Sort the array according to the requirements and print it out

2. Example

 public static void main(String[] args) {
 // TODO Auto-generated method stub
 try {
 //数组a()的数字个数，由用户输入决定
 InputStreamReader isr=new InputStreamReader(System.in);
 //从字符输入流中读取文本，缓冲各个字符，从而实现字符、数组和行的高效读取
 BufferedReader bfr=new BufferedReader(isr);
 //询问用户需要多少位数的数组
 System.out.println("请输入需要多少位数的数组：\n");
 String a1=bfr.readLine();
 //将a1转换为数字类型
 int i=Integer.parseInt(a1);
 //提示用户输入数组数据
 System.out.println("请向数组中存入"+i+"个数据：\n");
 //将用户输入数字存入数组
 Integer[] a=new Integer[i];
 for(int j=0;j<i;j++){
 System.out.println("第"+(j+1)+"个：");
 a[j]=new Integer(bfr.readLine());
 }
 //把数组按升序排序并打印出来
 for(int k=1;k<i;k++){
 for(int m=0;m<(i-k);m++){
 if(a[m]>a[m+1]){
 //Integer temp=new Integer(0);
 int temp=0;
 temp=a[m];
 a[m]=a[m+1];
 a[m+1]=temp;
 }
 }
 }
 //输出排序后的数组
 System.out.println("排序后\n");
 for(int t=0;t<=i;t++){
 System.out.println(a[t]);
 }
 
 } catch (Exception e) {
 // TODO: handle exception
 e.printStackTrace();
 }
 }
 
}

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