Home > Backend Development > PHP Tutorial > phpQuery让php处理html代码像jQuery一样方便_PHP

phpQuery让php处理html代码像jQuery一样方便_PHP

WBOY
Release: 2016-05-31 13:18:21
Original
877 people have browsed it

简介

如何在php中方便地解析html代码,估计是每个phper都会遇到的问题。用phpQuery就可以让php处理html代码像jQuery一样方便。

项目地址:https://code.google.com/p/phpquery/

github地址:https://github.com/TobiaszCudnik/phpquery

DEMO

下载库文件:https://code.google.com/p/phpquery/downloads/list

我下的是onefile版:phpQuery-0.9.5.386-onefile.zip

官方demo:https://code.google.com/p/phpquery/source/browse/branches/dev/demo.php

然后在项目中引用。

html文件test.html

代码如下:




php处理

代码如下:


    include('phpQuery-onefile.php');
   
    $filePath = 'test.html';
    $fileContent = file_get_contents($filePath);
    $doc = phpQuery::newDocumentHTML($fileContent);
    phpQuery::selectDocument($doc);
    $data = array(
        'name' => array(),
        'href' => array(),
        'img' => array()
    );
    foreach (pq('a') as $t) {
        $href = $t -> getAttribute('href');
        $data['href'][] = $href;
    }
    foreach (pq('img') as $img) {
        $data['img'][] = $domain . $img -> getAttribute('src');
    }
    foreach (pq('.GameName') as $name) {
        $data['name'][] = $name -> nodeValue;
    }
    var_dump($data);
?>

上面的代码中包含了取属性和innerText内容(通过nodeValue取)。

输出:

代码如下:


array (size=3)
  'name' =>
    array (size=2)
      0 => string 'Spiderman City Drive' (length=20)
      1 => string 'Spiderman - City Raid' (length=21)
  'href' =>
    array (size=2)
      0 => string 'http://www.gahe.com/Spiderman-City-Drive' (length=40)
      1 => string 'http://www.gahe.com/Spiderman-City-Raid' (length=39)
  'img' =>
    array (size=2)
      0 => string 'http://www.gahe.com/thumb/12/Spiderman-City-Drive.jpg' (length=53)
      1 => string 'http://www.gahe.com/thumb/12/Spiderman-City-Raid.jpg' (length=52)

强大的是pq选择器,语法类似jQuery,很方便。

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template