How to use lambda expression to sort in Java
1.lambda expression sorting
Let’s first look at a few common sorting examples, sorting of basic data types
List list = Arrays.asList(1,3,2,5,4); list.sort(Comparator.naturalOrder()); System.out.println(list); list.sort(Comparator.reverseOrder()); System.out.println(list); 输出结果: [1, 2, 3, 4, 5] [5, 4, 3, 2, 1]
We can see that the execution results are in line with expectations, but In most scenarios, we may need to sort a certain attribute of the object, so how should we do it? Let’s look at the example below:
public class Student { private String name; private String sexual; private Integer age; public Student(String name, String sexual,Integer age) { this.name = name; this.sexual = sexual; this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } public String getSexual() { return sexual; } public void setSexual(String sexual) { this.sexual = sexual; } public Integer getAge() { return age; } public void setAge(Integer age) { this.age = age; } @Override public String toString() { return "Student{" + "name='" + name + '\'' + ", sexual='" + sexual + '\'' + ", age=" + age + '}'; } public class Starter { public static void main(String[] args) { List<Student> list = Arrays.asList( new Student("jack", 12), new Student("john", 13), new Student("lily", 11), new Student("lucy", 10) ); list.sort(Comparator.comparing(Student::getAge)); System.out.println(list); list.sort(Comparator.comparing(Student::getAge).reversed()); System.out.println(list); } } 输出结果: [Student{name='lucy', age=10}, Student{name='lily', age=11}, Student{name='jack', age=12}, Student{name='john', age=13}] [Student{name='john', age=13}, Student{name='jack', age=12}, Student{name='lily', age=11}, Student{name='lucy', age=10}]
If we need to group and sort by gender, how should we do it? Let's look at the example below
public class Starter { public static void main(String[] args) { List<Student> list = Arrays.asList( new Student("jack", "male", 12), new Student("john", "male", 13), new Student("lily", "female", 11), new Student("david", "male", 14), new Student("luck", "female", 13), new Student("jones", "female", 15), new Student("han", "male", 13), new Student("alice", "female", 11), new Student("li", "male", 12) ); Map<String, List<Student>> groupMap = list.stream().sorted(Comparator.comparing(Student::getAge)) .collect(Collectors.groupingBy(Student::getSexual, Collectors.toList())); System.out.println(groupMap.toString()); } } 输出结果: { female = [ Student { name = 'lily', sexual = 'female', age = 11 }, Student { name = 'alice', sexual = 'female', age = 11 }, Student { name = 'luck', sexual = 'female', age = 13 }, Student { name = 'jones', sexual = 'female', age = 15 }], male = [ Student { name = 'jack', sexual = 'male', age = 12 }, Student { name = 'li', sexual = 'male', age = 12 }, Student { name = 'john', sexual = 'male', age = 13 }, Student { name = 'han', sexual = 'male', age = 13 }, Student { name = 'david', sexual = 'male', age = 14 }] }
We see that there is a problem with the output results above. If the ages are the same, they are not sorted by name. How to implement this function? Let’s look at the example below
Map<String, List<Student>> groupMap = list.stream().sorted(Comparator.comparing(Student::getAge) .thenComparing(Student::getName)).collect(Collectors.groupingBy(Student::getSexual, Collectors.toList())); 输出结果: { female = [ Student { name = 'alice', sexual = 'female', age = 11 }, Student { name = 'lily', sexual = 'female', age = 11 }, Student { name = 'luck', sexual = 'female', age = 13 }, Student { name = 'jones', sexual = 'female', age = 15 }], male = [ Student { name = 'jack', sexual = 'male', age = 12 }, Student { name = 'li', sexual = 'male', age = 12 }, Student { name = 'han', sexual = 'male', age = 13 }, Student { name = 'john', sexual = 'male', age = 13 }, Student { name = 'david', sexual = 'male', age = 14 }] }
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