golang array flip

When using golang for array operations, sometimes it is necessary to flip the array. So the question is, how to use golang to implement array flipping? This article will introduce two methods.

Method 1: Use for loop to flip array elements

Use for loop to flip array elements. The specific implementation steps are as follows:

1. Define array arr and variable n, n represents the array length.
2. Use a for loop to exchange the i-th element of the array arr with the n-i-1 element. The number of exchanges is n/2.
3. After the flip is completed, output the elements of the array arr.

The following is the specific code implementation:

package main

import (
    "fmt"
)

func main() {
    arr := []int{1, 2, 3, 4, 5}
    n := len(arr)

    for i := 0; i < n/2; i++ {
        arr[i], arr[n-i-1] = arr[n-i-1], arr[i]
    }

    fmt.Println(arr)
}

This code will output [5 4 3 2 1].

Method 2: Use the sort package to flip array elements

The sort package in golang provides the Reverse function, which can flip the array. The specific implementation steps are as follows:

1. Define the array arr.
2. Use the sort.Reverse function to reverse the array.
3. After the flip is completed, output the elements of the array arr.

The following is the specific code implementation:

package main

import (
    "fmt"
    "sort"
)

func main() {
    arr := []int{1, 2, 3, 4, 5}
    sort.Sort(sort.Reverse(sort.IntSlice(arr)))
    fmt.Println(arr)
}

This code will output [5 4 3 2 1].

Summary

Both methods can achieve flipping of array elements. Using a for loop is simpler and clearer, but using the sort package to implement the code is more concise and efficient. In actual development, the specific method to choose should be chosen based on actual needs and circumstances.

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