php7 cannot find the solution to the array index: 1. Create a PHP sample file; 2. Define the array variable $my_array; 3. Use the isset() or array_key_exists() function to check through the if judgment statement. Check whether the specified index exists in the array; 4. Just output the corresponding result or error message.
Operating system for this tutorial: Windows 10 system, php8.1.3 version, Dell G3 computer.
When a PHP program encounters a situation where the array index cannot be found (that is, the index does not exist in the array), a "Notice" level error message is usually thrown.
To solve this problem, you can use isset() or array_key_exists() function to check whether the specified index exists in the array.
The following is a code example:
// 定义一个数组 $my_array = array( 'apple' => 'red', 'banana' => 'yellow', 'orange' => 'orange' ); // 判断数组是否存在指定的键 if(isset($my_array['grape'])) { // 存在,则访问该元素 echo $my_array['grape']; } else { // 不存在,则提示用户或进行其他操作 echo "Sorry, no grape found!"; } // 或者使用array_key_exists()函数 if(array_key_exists('pear', $my_array)) { // 存在,则访问该元素 echo $my_array['pear']; } else { // 不存在,则提示用户或进行其他操作 echo "Sorry, no pear found!"; }
In the above example, an array containing three elements is defined. We then used the isset() and array_key_exists() functions to check whether the two indexes "grape" and "pear" exist in the array respectively. If it exists, access the element, otherwise output the corresponding error message.
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