Java backend development: API data conversion using Fastjson

WBOY
Release: 2023-06-17 08:16:01
Original
955 people have browsed it

With the rapid development of the Internet, the back-end development of web applications has become more and more important. As one of the core components of web applications, API data conversion plays an important role. API data conversion is the process of converting one data source into another format or structure. This process should be efficient, reliable, and easy to maintain. This article will guide you to use Fastjson to solve back-end API data conversion problems.

What is Fastjson?

Fastjson is a fast JSON parser and generator written in Java language. It is easy to use, high-performance, non-intrusive and powerful. The main goal of Fastjson is to parse and generate JSON data, but it also supports serializing and deserializing Java objects.

Why choose Fastjson?

Fastjson is a very good solution to the problem of Java backend API data conversion. Fastjson can quickly convert JSON strings into Java objects and can serialize Java objects into JSON format. Fastjson also supports high-performance data format conversion. For example, Java objects can be converted to other formats such as XML, CSV, and Excel. In addition, Fastjson supports JSONP and JSONPath, which is very useful when dealing with cross-domain data and data filtering.

Fastjson API data conversion example

Next, we will write a simple example to demonstrate API data conversion using Fastjson.

We will obtain JSON format data containing user information from an API and parse it into a Java object.

First, we need to define a Java class to store user information:

public class User {
    private int id;
    private String name;
    private int age;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}
Copy after login

Next, we will use Java HttpURLConnection to get JSON data from the API:

String url = "http://api.example.com/user/123";
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("GET");
int responseCode = con.getResponseCode();

BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuilder response = new StringBuilder();

while ((inputLine = in.readLine()) != null) {
    response.append(inputLine);
}
in.close();
Copy after login

Get After JSON data, we use Fastjson for conversion:

String jsonStr = response.toString();
User user = JSON.parseObject(jsonStr, User.class);
Copy after login

Finally, we will output user information:

System.out.println("ID: " + user.getId());
System.out.println("Name: " + user.getName());
System.out.println("Age: " + user.getAge());
Copy after login

Summary

Using Fastjson for API data conversion is Java backend development A very useful tool in . Fastjson is not only fast, but also supports multiple data format conversions. During future development, we recommend that you use Fastjson to solve API data conversion problems.

The above is the detailed content of Java backend development: API data conversion using Fastjson. For more information, please follow other related articles on the PHP Chinese website!

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template