复制代码 代码如下:
function getAgeByID($id){
//过了这年的生日才算多了1周岁
if(empty($id)) return '';
$date=strtotime(substr($id,6,8));
//获得出生年月日的时间戳
$today=strtotime('today');
//获得今日的时间戳
$diff=floor(($today-$date)/86400/365);
//得到两个日期相差的大体年数
//strtotime加上这个年数后得到那日的时间戳后与今日的时间戳相比
$age=strtotime(substr($id,6,8).' +'.$diff.'years')>$today?($diff+1):$diff;
return $age;
}
?>
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn