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Java program returns the largest element in a list

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Java program returns the largest element in a list

We can use array loop to return the largest element from the list. This is mainly achieved by comparing models. In a list, the largest number is compared to all elements in the list. The procedure will consider 'n' as input quantity and store it as data value in the array. Afterwards, the program will display the largest element on the output console after the loop ends.

In this article, we will help you understand and write some Java code through which you can find the largest element from an array list.

How to select the largest number from an array using Java?

We can find a largest number by sorting an array. To define a void ArrayList and add all elements of array to it. Passing the ArrayList to Collections.max() and the entire process will take a run.

  • For this operation, you can declare a set of input as a form of array at the beginning. This creates a base to execute a logic. The algorithm uses this loop to find out the particular result (largest number of that loop).

The Chinese translation of

Example

is:

Example

Let's take an example.

arr[]= {1,10,4,15,9,85,63,108}
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Output

Output: 108
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  • To find the largest number from an array, two types of functions are usually used -

    • Max () – Use to find the max function from the list

    • for Loop - Use to perform iteration for every element.

  • First, you should declare an array and then initialize it. For iteration we need two loops and then compare the elements to get the largest number and the data needs to be swapped in descending order.

Algorithm to find the largest element in a list

Here is the general algorithm for to find out the largest element in a list by using Java −

  • First Step − Start

  • Step 2 − Initialize arr[]

  • Step 3 − max=arr[0]

  • Step 4 − i=0;i

  • Step 4 - If (arr[i]>max)max=arr[i]

  • Step 5(1) − Print

  • Step 5(2) − Print MAX

  • Step 6 − Terminate

Syntax

There are two ways to perform this operation. Both methods are described in the syntax below.

  • coll means; the total collection from which the maximum element will be filtered out.

  • comp means; a comparator that can perform operations.

public static <T extends an Object & make it Comparable<? super T>> T max(Collection of data <? extends T> coll)  
  or;
public static <T> T max(Collection of the data <? extends T> coll, Comparator<? super T> comparator)
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Below approaches are useful for finding out the largest value in an array list −

  • Method 1 - Iterative method

  • Approach 2 − Int method by Java 8 stream

  • Approach 3 − max() method

  • Approach 4 − Using ForEach Loop

  • Approach 5 − Using Library Function

By Using the Iteration Method

In this method, the time complexity is based on the size of the given data set being 0. And no additional auxiliary space is required.

  • Recursive way to get max value.

  • Basic Condition of the method: if , (m==1) value return arr[0]

  • Else, get return the value of: maximum (arr[n-1], getmax(arr[], n-1))

The Chinese translation of

Example

is:

Example

import java.util.*;  
public class CollectionsofmaxfileARRDD {  
   public static void main (String[] args) {  
      List<Integer> list = Arrays.asList(2010, 1010, 1001, 1400, 2501);  
      Integer max = Collections.max(list, Collections.reverseOrder());  
      System.out.println("Output from the particular string: "+max);  
   }  
}    
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Output

Output from the particular string: 1001
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By using Int method in Java 8 Stream

In this method the time complexity is totally 0 and the auxiliary space has no extra space needed because it is constant.

The Chinese translation of

Example

is:

Example

import java.util.Arrays;
public class arbrdd {
   public static void main (String[] args){
      int arr[] = {07, 16, 10, 2001, 1997};
      int max = Arrays.stream(arr).max().getAsInt();
      System.out.println("Largest array is found from the array list" +max);
   }
}     
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Output

Largest array is found from the array list2001
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By Using the max() Method

By using the max() method, we will build the Java code using the following process -

  • Declare a variable with a maximum value

  • Initialize with the first element of an array

  • Run loop

  • array[a]>maximum, set max = array[a]

  • Print output

The Chinese translation of

Example

is:

Example

import java.util.*;
public class arbrdd{
   public static void main(String[] args){
      int arr[] = {10, 07, 16, 2001,1997};
      List<Integer> list = new ArrayList<>();
      for(int a=0;a<arr.length;a++){
         list.add(arr[a]);
      }
      System.out.println("Largest array present in the particular array list is " +Collections.max(list));
   }
}    
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Output

Largest array present in the particular array list is 2001
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By using a ForEach loop

By using ForEach loop, we will build the Java code using the following process -

  • Call recursive say get max

  • Basic conditions for operation: if, (a==1) return array [0]

  • Otherwise, return max(array[a-1], getmax(array, a-1))

The Chinese translation of

Example

is:

Example

import java.util.Arrays;
import java.util.List;
public class maxarrayval {
   public static void main(String[] args){
      List<Integer> arrayList
      = Arrays.asList(10, 07, 16, 2001, 1997, 10052022);
      int maxValue0710 = Integer.MIN_VALUE;
      for (Integer integer : arrayList) {
         if (integer > maxValue0710)
         maxValue0710 = integer;
      }
      System.out.println("The maximum value present in the array is " + maxValue0710);
   }
}   
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Output

The maximum value present in the array is 10052022
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By Using Library Function

By using the library functions, here we will build a Java code by using the below process −

  • Maximum(arr,0,end)

  • Read the penultimate element from the array list

  • Find the larger element between 2nd last and last one from array data

  • Max value recursive iteration

  • 结束

Example

的中文翻译为:

示例

import java .io.*;
import java.util.*;
public class ARBRDD{
   static int largest(int []arr,int n){
      Arrays.sort(arr);
      return arr[n - 1];
   }
   static public void main (String[] args){
      int []arr = {07, 10, 2001,1997, 10052022};
      int n = arr.length;
      System.out.println(largest(arr, n));
   }
}   
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输出

10052022
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结论

In this article; today we learnt how to get the Largest Element in return from an array List using Java.

通过可能的条件和使用此处提到的逻辑编写的程序,我们如何使用数组循环,并根据所有可能的条件和此处编写的一些代码的处理过程来满足每个理论。

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source:tutorialspoint.com
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