php 上一篇,下一篇文章实现代码与原理说明_PHP

WBOY
Release: 2016-06-01 12:18:12
Original
879 people have browsed it

实现原理:

就是对id对进行order by id desc 或 order by id asc进行排序,然后再判断比当前id> or小于当前文章id的相同栏目的文章。
实例的sql语句如下:

$id就是当面文章的id

select * from news where idselect * from news where id>$id order by id desc limit 0,1

--
-- 表的结构 `string_find`
--

CREATE TABLE IF NOT EXISTS `string_find` (
`id` int(4) NOT NULL auto_increment,
`charList` varchar(100) default NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=7 ;

--
-- 导出表中的数据 `string_find`
--

INSERT INTO `string_find` (`id`, `charList`) VALUES
(1, ''),
(2, 'baidu'),
(5, 'www.baidu.com'),
(6, 'www.bitsCN.com');

好了万事俱备了,下面来看一下操作方法

复制代码 代码如下:
mysql_connect('localhost','root','root') or die(mysql_error());
mysql_select_db('cc');
mysql_query("set names 'gbk'");
$cid =5;//是你当前文章的编号
$sql ="select * from string_find where id>$cid order by id desc limit 0,1"; //上一篇文章
$sql1 ="select * from string_find where id
$result = mysql_query( $sql );
if( mysql_num_rows( $result ) )
{
$rs = mysql_fetch_array( $result );
echo "上一篇".$rs[0];
}
else
{
echo "没有了";
}

$result1 = mysql_query( $sql1 );
if( mysql_num_rows( $result1 ) )
{
$rs1 = mysql_fetch_array( $result1 );
echo "下一篇".$rs1[0];
}
else
{
echo "没有了";
}


以下是别的网友写的文章。
由于我希望访客在浏览网页的时候需要看到上一主题,下一主题的标题,所以必定是要在数据库中查询出来的了,可以通过limit限制来取,比如,我的博客是按照ID自动增量的,那么可以通过查找大于或者小于当前ID来取

$UpSQL="SELECT * FROM `blog` WHERE `ID`$DownSQL="SELECT `ID`,`Title` FROM `blog` WHERE `ID`> $id ORDER BY `ID` ASC LIMIT 0,1";

再通过查询,取出数据
如果只是单一的"上一篇","下一篇"那么就没有必要查询了,这样是不必查询了,但也许用户点击之后会看到,这已经是首页了或者这已经是末页了,呵呵
复制代码 代码如下:
switch($act) {
case "Up":
$SQL="SELECT * FROM `blog` WHERE `ID`break;
case 'Down':
$SQL="SELECT * FROM `blog` WHERE `ID`> $id ORDER BY `ID` ASC LIMIT 0,1";
break;
default :
$SQL="SELECT * FROM `blog` WHERE `ID`= $id LIMIT 0,1";
break;
}

通过传递一个动作来实现上一主题,下一主题

Related labels:
php
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!