C program to display numbers in X form

Refer to the algorithm below and write a C program to display X-shaped numbers.

Algorithm

Step 1: Start
Step 2: Declare variables
Step 3: Read number of rows
Step 4: for loop satisfies<ul class="list"><li>if(i==j || i+j==rows-1)<ul class="list"><li>print i+1</li></ul></li><li>Print " "</li></ul>Step 5: Print new line
Step 6: Stop

The logic to print numbers in X pattern is as follows −

for(i=0;i<rows;i++){
   for(j=0;j<rows;j++){
      if(i==j || i+j==rows-1){
         printf("%d",i+1);
      }else{
         printf(" ");
      }
   }
   printf("</p><p>");
}

Program

Following is the C program to display the numbers in X pattern −

#include<stdio.h>
main(){
   int i,j,rows;
   printf("Enter number of rows:</p><p>");
   scanf("%d",&rows);
   for(i=0;i<rows;i++){
      for(j=0;j<rows;j++){
         if(i==j || i+j==rows-1){
            printf("%d",i+1);
         }else{
            printf(" ");
         }
      }
      printf("</p><p>");
   }
}

Output

When the above program is executed, it produces the following result−

Enter number  of rows:10
1           1
  2        2
    3    3
      4 4
       55
       66
      7 7
    8     8
  9        9
10          10

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