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In a C program, what is the area of ​​a hexagon given the length of its diagonal?

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Release: 2023-08-27 10:25:06
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In a C program, what is the area of ​​a hexagon given the length of its diagonal?

A hexagon is a closed figure of a hexagon, and a regular hexagon is a hexagon with six equal sides and equal angles. To find the area of ​​a hexagon, we are given only the length of its diagonal, which is d.

Each interior angle of a hexagon is 120 degrees, and the sum of all angles of a hexagon is 720 degrees.

The formula to find the area of ​​a hexagon with side length a,

Area = (3a<sup>2</sup> &radic;3) / 2.
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Since all sides are the same size and the angle is 120 degrees,

d = 2a or a = d/2
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By changing the value of a Denoted as d, we get the area with respect to d. The Chinese translation of

2 &radic;3 ) / 8
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Example

is:

Example

#include <stdio.h>
#include<math.h>
int main() {
   float d = 10;
   float area = (3 * sqrt(3) * pow(d, 2)) / 8;
   printf("Area of hexagon = %f",area);
   return 0;
}
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Output

Area of hexagon = 64.951904
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source:tutorialspoint.com
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