C program to calculate distance between three points in 3D space

Given a three-dimensional plane and therefore three coordinates, the task is to find the distance between the given points and display the result.

On the three-dimensional plane, there are three coordinate axes. The coordinates of the x-axis are (x1, y1, z1), the coordinates of the y-axis are (x2, y2, z2), and the coordinates of the z-axis are (x3, y3,z). There is a direct formula for calculating the distance between them as follows

$$\sqrt{\lgroup x2-x1\rgroup^{2} \lgroup y2-y1\rgroup^{2} \lgroup z2 -z1\rgroup^{2}}$$

The following is a diagram showing three different axes and their coordinates

The method used below is as follows −

• Input coordinates (x1, y1, z1), (x2, y2, z2) and (x3, y3, z3)
• Apply the formula to calculate the difference between these points
• Print distance

Algorithm

Start
Step 1-> declare function to calculate distance between three point
   void three_dis(float x1, float y1, float z1, float x2, float y2, float z2)
      set float dis = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) + pow(z2 - z1, 2) * 1.0)
      print dis
step 2-> In main()
   Set float x1 = 4
   Set float y1 = 9
   Set float z1 = -3
   Set float x2 = 5
   Set float y2 = 10
   Set float z2 = 9
   Call three_dis(x1, y1, z1, x2, y2, z2)
Stop

Example

's translation is:

Example

#include <stdio.h>
#include<math.h>
//function to find distance bewteen 3 point
void three_dis(float x1, float y1, float z1, float x2, float y2, float z2) {
   float dis = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) + pow(z2 - z1, 2) * 1.0);
   printf("Distance between 3 points are : %f", dis);
   return;
}
int main() {
   float x1 = 4;
   float y1 = 9;
   float z1 = -3;
   float x2 = 5;
   float y2 = 10;
   float z2 = 9;
   three_dis(x1, y1, z1, x2, y2, z2);
   return 0;
}

Output

If we run the above code it will generate the following output

Distance between 3 points are : 12.083046

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