Solving interesting pattern problems can enhance understanding of loops. They are essential because they help build a solid foundation in a specific programming language. There are various modes, including number-based, asterisk-based, and letter-based modes. This article will guide you to solve a cabin star schema using nested for loops in Java.
Since we are going to use nested for loops to solve the problem, it is necessary to discuss its syntax.
for ( initial expression; conditional expression; increment/decrement expression ){ for ( initial expression; conditional expression; increment/decrement expression ) { // code to be executed } }
Initial expression - Executed once at the beginning of the loop.
Conditional Expression - The code will be executed when the conditional expression is true.
Increment/decrement expression - Increment/decrement loop variable.
The Chinese translation ofDivide the entire pattern into two parts. The first part is an upper triangular shape and the second part is a lower rectangular part.
Declare and initialize an integer "n", specifying the number of lines in the upper and lower parts.
Declare and initialize the initial count of spaces and stars.
Now, define a nested for loop for the upper triangle part. The outer for loop will run to "n" and the first inner loop will run to the space count and print the spaces. Decrease the number of spaces by 1 after printing.
The second inner for loop will run until the stars are counted, and the stars will be printed. Increase the star count by 2 after printing.
Create another nested for loop again. The outer for loop will run till 'n', the first inner loop will print the left rectangle shape, the second inner loop will print spaces and the last inner loop will print the right rectangle shape.
public class Hut { public static void main(String[] args) { // count of upper triangle row and lower rectangle row int n = 5; int spc = n-1; // initial count of space int str = 1; // initial count of star // upper triangular shape for(int i = 1; i <= n; i++) { for(int j = 1; j <= spc; j++) { // for space System.out.print("\t"); } spc--; for(int k = 1; k <= str; k++) { // for star System.out.print("*\t"); } str += 2; System.out.println(); // to move the cursor to next line } // lower rectangular shape for (int i = 0; i < n; i++) { // for left rectangular shape for (int j = 0; j < n/2; j++) { System.out.print("*\t"); } // for space for (int j = 0; j < 5; j++) { System.out.print("\t"); } // for right rectangular shape for (int j = 0; j < n/2; j++) { System.out.print("*\t"); } System.out.println(); // to move the cursor to next line } } }
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In this article, we discussed the solution for Hut Star Schema. We solved this particular problem with the help of nested for loops. This will help you decode the logic of pattern problems and enable you to solve other patterns on your own.
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