How to exchange the values ​​of two arrays in C language without using temporary variables?

Exchange two arrays without using temporary variables. Here we will use arithmetic and bitwise operators instead of the third variable.

The logic of reading the first array is as follows:-

printf("enter first array ele:</p><p>");
for(i = 0; i < size; i++){
   scanf("%d", &first[i]);
}

The logic of reading the second array is as follows-

printf("enter first array ele:</p><p>");
for(i = 0; i < size; i++){
   scanf("%d", &first[i]);
}

Do not use the third variable exchange The logic of the two arrays is as follows −

for(i = 0; i < size; i++){
   first[i] = first[i] + sec[i];
   sec[i] = first[i] - sec[i];
   first[i] = first[i] - sec[i];
}

Program

The following is a C program to exchange two arrays without using temporary variables:

Online demonstration

#include<stdio.h>
int main(){
   int size, i, first[20], sec[20];
   printf("enter the size of array:");
   scanf("%d", &size);
   printf("enter first array ele:</p><p>");
   for(i = 0; i < size; i++){
      scanf("%d", &first[i]);
   }
   printf("enter second array ele:</p><p>");
   for(i = 0; i < size; i ++){
      scanf("%d", &sec[i]);
   }
   //Swapping two Arrays
   for(i = 0; i < size; i++){
      first[i] = first[i] + sec[i];
      sec[i] = first[i] - sec[i];
      first[i] = first[i] - sec[i];
   }
   printf("</p><p> first array after swapping %d elements</p><p>", size);
   for(i = 0; i < size; i ++){
      printf(" %d \t ",first[i]);
   }
   printf("sec array after Swapping %d elements</p><p>", size);
   for(i = 0; i < size; i ++){
      printf(" %d \t ",sec[i]);
   }
   return 0;
}

Output

When the above program is executed, it produces the following results −

enter the size of array:5
enter first array ele:
11 12 13 14 15
enter second array ele:
90 80 70 60 50
first array after swapping 5 elements
90 80 70 60 50
sec array after Swapping 5 elements
11 12 13 14 15

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