Write a C program to print numbers as words using elseif statement

Question

How to print a given number in literal form using C programming language without using switch case?

Solution

In this program we check three conditions to print two digits in words-

• if(no 99)

  • if(no99) p>

    The number entered is not a two-digit number

  • else if( no==0)

    Print the first number as zero

  • else if(no>=10 && no

    Print single digits in text

  • else if(no>=20 && no

    if(no == 0)

    Print two digits with text

  Program

  Live demonstration

  #include<stdio.h>
  #include<string.h>
  int main(){
     int no;
     char *firstno[]={"zero","ten","eleven","twelve","thirteen", "fourteen","fifteen","sixteen","seventeen", "eighteen","nineteen"};
     char *secondno[]={"twenty","thirty","forty","fifty","sixty", "seventy","eighty","ninty"};
     char *thirdno[]={"one","two","three","four","five","six","seven","eight","nine"};
     printf("enter a number:");
     scanf("%d",&no);
     if(no<0 || no>99)
        printf("enter number is not a two digit number</p><p>");
     else if(no==0)
        printf("the enter no is:%s</p><p>",firstno[no]);
     else if(no>=10 && no<=19)
        printf("the enter no is:%s</p><p>",firstno[no-10+1]);
     else if(no>=20 && no<=90)
        if(no%10 == 0)
           printf("the enter no is:%s</p><p>",secondno[no/10 - 2]);
     else
        printf("the enter no is:%s %s</p><p>",secondno[no/10-2],thirdno[no%10-1]);
  return 0;
  }

  Output

  enter a number:79
  the enter no is: seventy nine
  enter a number:234
  enter number is not a two digit number

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