C program to check if a given string is a keyword?

Keywords are words that are predefined or reserved in the C library, have a fixed meaning, and are used to perform internal operations. The C language supports more than 64 keywords.

Each keyword exists in lowercase letters, such as auto, break, case, const, continue, int, etc.

The 32 keywords in C language can also be used in C language.

auto	double	int	struct
break	else	long	switch
case	enum	register	typedef
char	extern	return	union
const	float	short	unsigned
continue	for	signed	void
default	goto	sizeof	volatile
do	if	static	while

##This is in C The newly added 30 reserved words are not in C language.

asmdynamic_castnamespacereinterpret_castboolexplicitnewstatic_cast##catchclassconst_castdeletetryusing

false	operator	template
friend	private	this
inline	public	throw
mutable	protected	true
typeid	typename	using
using	wchar_t

Input: str=”for”
Output: for is a keyword

Explanation

Keywords are reserved words that cannot be used as variable names in the program.
There are 32 keywords in the C programming language.
Compares the string with each keyword, if the strings are the same, then the string is a keyword.

Example

Example

#include <stdio.h>
#include <string.h>
int main() {
   char keyword[32][10]={
      "auto","double","int","struct","break","else","long",
      "switch","case","enum","register","typedef","char",
      "extern","return","union","const","float","short",
      "unsigned","continue","for","signed","void","default",
      "goto","sizeof","voltile","do","if","static","while"
   } ;
   char str[]="which";
   int flag=0,i;
   for(i = 0; i < 32; i++) {
      if(strcmp(str,keyword[i])==0) {
         flag=1;
      }
   }
   if(flag==1)
      printf("%s is a keyword",str);
   else
      printf("%s is not a keyword",str);
}

Output

which is a keyword

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