The challenge is to display the pattern using only a loop and continue statement.
START Step 1 -> declare start variables i and j to 0 with number of rows in n to 6 Step 2 -> Loop For i=1 and i<=n IF j<i Print * Increment j by 1 Continue End IF IF j=1 Print </p><p> Set j=0 Increment i by 1 End IF Step 3 -> End For Loop STOP
#include <stdio.h> int main() { int i, j=0; int n = 6; for ( i = 1; i <= n; ) { if( j < i ) { printf("*"); j++; continue; } if(j == i) { printf("</p><p>"); j = 0; i++; } } return 0; }
If we run the above program then it will generate the following output
* ** *** **** ***** ******
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