Given an array of size n and multiple integer values, we need to rotate the array starting from the given index k.
We want to rotate the array starting from index k as shown below- p>
Input: arr[] = {1, 2, 3, 4, 5} K1 = 1 K2 = 3 K3 = 6 Output: 2 3 4 5 1 4 5 1 2 3 2 3 4 5 1
START Step 1 -> Declare function void leftRotate(int arr[], int n, int k) Declare int cal = k% n Loop For int i=0 and i<n and i++ Print arr[(cal+i)%n] End Step 2 -> In main() Declare array a[]={ 1,2,3,4} Declare int size=sizeof(a)/sizeof(a[0]) Declare int k=1 Call leftRotate(a, size, k) Set k=2 Call leftRotate(a, size, k) Set k=3 leftRotate(a, size, k) STOP
#include <bits/stdc++.h> using namespace std; void leftRotate(int arr[], int n, int k){ int cal = k % n; for (int i = 0; i < n; i++) cout << (arr[(cal + i) % n]) << " "; cout << "</p><p>"; } int main(){ int a[] = { 1,2,3,4}; int size = sizeof(a) / sizeof(a[0]); int k = 1; leftRotate(a, size, k); k = 2; leftRotate(a, size, k); k = 3; leftRotate(a, size, k); return 0; }
If we run the above program then it will generate the following output
2 3 4 1 3 4 1 2 4 1 2 3
The above is the detailed content of Print left rotation of array in C program with O(n) time complexity and O(1) space complexity. For more information, please follow other related articles on the PHP Chinese website!