Discuss a problem in which the ratio of the sum of m and n terms of A.P is given. We need to find the ratio of the mth term to the nth term.
Input: m = 8, n = 4 Output: 2.142 Input: m = 3, n = 2 Output: 1.666 Input: m = 7, n = 3 Output: 2.6
To find the ratio of the mth term to the nth term using code, we need to simplify the formula. Let Sm be the sum of the first m terms and Sn be the sum of the first n terms of A.P.
a - the first item,
d - the tolerance,
is given, Sm / Sn = m2< /sup> / n2
#S formula, Sm = (m/2)[ 2*a (m -1)*d]
m2 / n2 = (m/2)[ 2*a (m-1)*d ] / (n/2)[ 2*a (n-1)*d ]
m / n = [ 2*a (m-1) *d ] / [ 2*a (m-1) * d ]
Use cross multiplication,
n[ 2*a (m−1)*d ] = m[ 2*a (n− 1)*d]
2an mnd - nd = 2am mnd - md
2an - 2am = nd - md
(n - m)2a = (n-m)d
2an - 2am = nd 2a
The formula for the mitem is:
Tm = a (m-1)d
The ratio of the mth item to the nth item is,
Tm / Tn = a (m -1)d / a (n-1)d
Replace d with 2a, Tm / Tn = a (m-1)*2a / a (n-1)*2a tm / tn = a (1 2m − 2) / a (1 2N − 2) #TM / TN = 2m -1 / 2n -1So now we have a simple formula for finding the ratio of the m
thth term to the nthth term. Let's take a look at the C code. Example
C code for the above method#include <bits/stdc++.h>
using namespace std;
int main(){
float m = 8, n = 4;
// calculating ratio by applying formula.
float result = (2 * m - 1) / (2 * n - 1);
cout << "The Ratio of mth and nth term is: " << result;
return 0;
}
The ratio of mth and nth term is: 2.14286
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