Print unique elements in a sorted array in C

Given an array of integer elements, the task is to remove duplicate values ​​and print out the different elements in a sorted manner.

Given below is an array that stores integer type values ​​in the order of 4, 6, 5, 3, 4, 5, 2, 8, 7 and 0. Now, the result will be 0, 2, 3 , 4, 4, 5, 5, 6, 7 and 8 print out the sorted elements in the order, but this result still contains duplicate values ​​4 and 5, they should be removed, the final result will be 0, 2, 3, 4, 5, 6, 7 and 8

##Example

Input: array[] = {4, 6, 5, 3, 4, 5, 2, 8, 7, 0}
Output: 0 2 3 4 5 6 7 8

Explanation

So, to achieve our goal, we will

Store different elements in another array array1.
Sort array1.
Print the value of array1.

Algorithm

START
   STEP 1: DECLARE VARIABLES i, j, array1[size], temp, count = 0
   STEP 2: LOOP FOR i = 0 AND i < size AND i++
      LOOP FOR j = i+1 AND j < size AND j++
         IF array[i] == array[j]) then,
            break
         END IF
      END FOR
      IF j == size then,
         ASSIGN array1[count++] WITH array[i]
      END IF
   END FOR
   STEP 3: LOOP FOR i = 0 AND i < count-1 AND i++
      LOOP FOR j = i+1 AND j < count AND j++
         IF array1[i]>array1[j] then,
            SWAP array1[i] AND array[j]
         END IF
      END FOR
   END FOR
   STEP 4: PRINT array1
STOP

Example

#include <stdio.h>
/* Prints distinct elements of an array */
void printDistinctElements(int array[], int size) {
   int i, j, array1[size], temp, count = 0;
   for(i = 0; i < size; i++) {
      for(j = i+1; j < size; j++) {
         if(array[i] == array[j]) {
            /* Duplicate element found */
            break;
         }
      }
      /* If j is equal to size, it means we traversed whole
      array and didn&#39;t found a duplicate of array[i] */
      if(j == size) {
         array1[count++] = array[i];
      }
   }
   //sorting the array1 where only the distinct values are stored
   for ( i = 0; i < count-1; i++) {
      for ( j = i+1; j < count; j++) {
         if(array1[i]>array1[j]) {
            temp = array1[i];
            array1[i] = array1[j];
            array1[j] = temp;
         }
      }
   }
   for ( i = 0; i < count; ++i) {
      printf("%d ", array1[i]);
   }
}
int main() {
   int array[] = {4, 6, 5, 3, 4, 5, 2, 8, 7, 0};
   int n = sizeof(array)/sizeof(array[0]);
   printDistinctElements(array, n);
   return 0;
}

Output

If we run the above program , which will generate the following output.

0 2 3 4 5 6 7 8

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