How to implement the interrupt and continue functions in online answering

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Release: 2023-09-25 15:06:01
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How to implement the interrupt and continue functions in online answering

How to implement the interrupt and continue functions in online answering?

Online answering questions has become a popular way of learning, but sometimes we may encounter some emergencies and need to interrupt answering questions, or we may need to continue answering the remaining questions at a later time. This article will introduce in detail how to implement the interrupt and continue functions in online answering, and provide specific code examples.

1. Implementation of the answer interruption function:

  1. First, add an "Interrupt Answer" button on the answer page. After the user clicks the button, an event will be triggered to record the progress of the current answer.
  2. In the event of recording progress, we can use the browser's localStorage or sessionStorage to save the status of the current answer. The specific code is as follows:
// 点击中断答题按钮的事件
function interruptAnswer() {
  // 获取当前答题的进度,可以是当前答到第几题或者已回答的题目ID集合等等
  var progress = getAnswerProgress();
  
  // 使用localStorage保存答题进度
  localStorage.setItem('answer_progress', JSON.stringify(progress));
  
  // 跳转到其他页面或进行其他操作
  // ....
}

// 获取当前答题进度的函数
function getAnswerProgress() {
  // 获取当前答到第几题或者已回答的题目ID集合等等
  var progress = // 根据实际情况获取当前答题进度;
  return progress;
}
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  1. When the user needs to continue answering questions, we can check whether the answering progress exists in localStorage in the initialization function of the answering page. If it exists, restore the answering progress. . The specific code is as follows:
// 初始化答题页面
function initAnswerPage() {
  // 检查localStorage中是否存在答题进度
  var progress = JSON.parse(localStorage.getItem('answer_progress'));
  
  // 如果存在答题进度,则恢复答题进度
  if(progress) {
    restoreAnswerProgress(progress);
  }
  
  // 继续答题
  continueAnswer();
}

// 恢复答题进度的函数
function restoreAnswerProgress(progress) {
  // 根据进度恢复答题状态,可以是跳转到指定的题目、显示已答题目的标记等等
  // ....
}

// 继续答题的函数
function continueAnswer() {
  // ....
}
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2. Implementation of the answer continuation function:

  1. In the initialization function of the answer page, you can also check whether there is answer progress in localStorage. If If exists, the progress of answering the question will be resumed and jump to the question when the answer was last interrupted. The specific code is as follows:
// 初始化答题页面
function initAnswerPage() {
  // 检查localStorage中是否存在答题进度
  var progress = JSON.parse(localStorage.getItem('answer_progress'));
  
  // 如果存在答题进度,则恢复答题进度
  if(progress) {
    restoreAnswerProgress(progress);
  }
  
  // 继续答题
  continueAnswer();
}

// 恢复答题进度的函数
function restoreAnswerProgress(progress) {
  // 根据进度恢复答题状态,可以是跳转到上次中断的题目、显示已答题目的标记等等
  // ....
}

// 继续答题的函数
function continueAnswer() {
  // ....
}
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Through the above code examples, we can implement the interrupt and continue functions in online answering. When the user needs to interrupt answering questions, click the "Interrupt Answering" button to save the current answering progress and perform other operations; when the user needs to continue answering questions, after entering the answering interface, the answering status can be restored based on the previously saved answering progress, and Continue to answer questions.

Please note that when using localStorage or sessionStorage to save your answer progress, you must consider browser compatibility and privacy protection, and try to avoid saving sensitive information. At the same time, in order to ensure a normal user experience, we must also pay attention to the impact of page refresh, logout and other operations on the answering progress. We can clear or update the answering progress record at the appropriate time.

I hope this article can help you implement the interrupt and continue functions in online answering.

The above is the detailed content of How to implement the interrupt and continue functions in online answering. For more information, please follow other related articles on the PHP Chinese website!

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